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Answer:

all true

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Which function represents the equation of the line? A. f(x)= -x-4B. f(x)= -x+4C. f(x)= x-4D. f(x)= x+4
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How much is 1,000 milligrams in ounces?

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0.035274 ounces (oz) is the coversion of 1000 miligrams to ounces

What is the difference between 126 1
/4
and 78 2
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The answer of that is 47 7/12

Please help me solve this question.

Answers

Cut the sign in half across its middle. Then you have two right triangles.
They're congruent, so pick one to work with, and discard the other one
temporarily.

In the right triangle:

-- The length of one leg is 'x'.
-- The length of the other leg is (2x + 7).
-- The length of the hypotenuse is 35.47 inches.

You know that in any right triangle:

(The square of the hypotenuse) =
(the square of one leg) + (the square of the other one.)

so you can use that to find the value of 'x'.

One you know the value of 'x', go back to the whole sign before you cut it
in half, and notice that the height of the sign is '2x' ... which is the answer.

height =2x so we must find x then multiply by 2

if we cut the triangle in half from with the line from left to right, we have a trianlgle that is x high and 2x+7 wide and the hyposonuse that is 35.47 so
a^2+b^2=c^2
x^2+(2x+7)^2=35.47^2
x^2+4x^2+28x+49=1258.12
group like terms
5x^2+28x+49=1258.12
subtract 1258.12 from both sides
5x^2+28x-1209.12=0
factor 5(x-13.0008)(x+18.6008)=0
therefore
(x-13.0008) or/and (x+18.6008)=0
x-13.0008=0
add 13.0008 to both sides
x=13.0008

x+18.6008=0
subtract 18.6008 from both sides
x=-18.6008
since heights cannot be negative, this solution can be discarded

so x=13.0008
2x=height=26.0016

The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the standard form of the equation for this line?

Answers

The equation of line passes through points $\left({ - \,4, - \,3}\right)$ and $\left({12,1}\right)$ in standard form is $\boxed{{\mathbf{x - 4y = 8 }}}$ .

Further explanation:

It is given that a line passes through points $\left({ - 4, - 3}\right)$ and $\left({12,1}\right)$ .

The slope of a line passes through points $\left({{x_1},{y_1}}\right)$ and $\left({{x_2},{y_2}}\right)$ is calculated as follows:

$m=\frac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}{\text{ }}$ ......(1)

Here, the slope of a line is denoted as and points are $\left({{x_1},{y_1}}\right)$ and $\left({{x_2},{y_2}}\right)$ .

Substitute for ${x_1}$ , $-3$ for ${y_1}$ , $12$ for ${x_2}$ and $1$ for ${y_2}$ in equation (1) to obtain the slope of a line that passes through points $\left({ - 4, - 3}\right)$ and $\left({12,1}\right)$ .

$\begin{aligned}m&=\frac{{1 - \left({ - 3}\right)}}{{12 - \left({ - 4}\right)}}\n&=\frac{{1 + 3}}{{12 + 4}}\n&=\frac{4}{{16}}\n&=(1)/(4)\n\end{aligned}$

Therefore, the slope is $(1)/(4)$ .

The point-slope form of the equation of a line with slope $m$ passes through point $\left({{x_1},{y_1}}\right)$ is represented as follows:

$y - {y_1}=m\left({x - {x_1}}\right){\text{}}$ ......(2)

Substitute for ${x_1}$ , $1$ for ${y_1}$ and $(1)/(4)$ for $m$ in equation (2) to obtain the equation of line.

$\begin{aligned}y - 1&=(1)/(4)\left({x - 12}\right)\n4\left({y - 1}\right)&=x - 12\n4y - 4&=x - 12\nx - 4y&=8\n\end{aligned}$

Therefore the standard equation of line that passes through points $\left({ - 4, - 3}\right)$ and $\left({12,1}\right)$ is $x - 4y = 8$ .

Thus, theequation of line passes through points $\left({ - 4, - 3}\right)$ and $\left({12,1}\right)$ in standard form is $\boxed{{\mathbf{x - 4y = 8 }}}$

Learn more:

1. Which classification best describes the following system of equations? brainly.com/question/9045597

2. What is the value of in the equation when ? brainly.com/question/3965451

3. What are the values of x?brainly.com/question/2093003

Answer Details:

Grade: Junior High School

Subject: Mathematics

Chapter: Coordinate Geometry

Keywords:Coordinate Geometry, linear equation, system of linear equations in two variables, variables, mathematics,equation of line, line, passes through point

There are 2,100 bacteria in a circular petri dish. The dish has a radius of 40 millimeters. What is the approximate population density? (Use 3.14 for π)

Answers

A petri dish is simply a circle; thus, we use the formula of the area of the circle which is πr^2.
Given r = 40 mm
A = π(40)^2 = 5026.55 sq. mm

Population density = bacteria count / area
PD = 2,100 / 5026.55
PD = 0.417782 bacteria / mm sq.

Therefore, the answer is approximately 0.418 bacteria per square millimeter.

Determine the area of the circular petri dish through the equation, A = πr^2. Substituting the radius to the equation and solving for area gives, 5024 mm^2. The population density is obtained by dividing the population with the calculated area. Thus, the population density is approximately 0.418 bacteria per mm^2.

What is the value of the element at h21? H= [6, 52, -4]
[15, 9, 75]
[-1, 23, 2]