The steeper line is determined by comparing the slopes of the two lines. The line with the larger slope value is the steeper line. However, the actual slopes of Line A and Line B in the question are not provided.
From the question, it seems like there are two given lines - Line A and Line B but no specific data is provided about their slopes. Therefore, with the information given, we can't determine which line has the steeper slope. Essentially, the steeper line would be the one with the higher slope value when represented in the form: y = mx + c, where 'm' is the slope. For instance, if Line A had an equation of y = 2x +1 and Line B an equation of y = 4x + 1, Line B's slope is steeper because it has a larger 'm' value compared to Line A.
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Answer:
y = - x +
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
given the line with equation
y = - x + 7 ← in slope- intercept form
with slope m = -
• Parallel lines have equal slopes , then
y = - x + c ← is the partial equation of the parallel line
to find c, substitute the point (3, 3 ) for x/ y into the partial equation
3 = - (3) + c = - + c ( add to both sides )
+ = c , that is
c =
y = - x + ← equation of parallel line
The equation of the line passing through point (3,3) and parallel to y = -(1/6)x + 7 is y = -(1/6)x + 3.5, which is achieved by knowing that parallel lines have the same slope and substituting the coordinates of the given point into the y = mx + b (slope-intercept form) and solving for the y-intercept 'b'.
The question asks for an equation of a line that is parallel to the equation y = -(1/6)x + 7 and also passes through the point (3,3). First, it's significant to understand that parallel lines share the same slope. Looking at the equation y = -(1/6)x + 7, we can see that the slope, or 'm' value, is -1/6. Therefore, the slope of our new line will also be -1/6. The conventional form of the equation for a line is y = mx + b where m is the slope and b is the y-intercept. Since we know the slope and have a point that lies on the line, we can substitute these values into this formula to solve for 'b'.
Here's how we do it:
First, substitute the point's coordinates into the equation for the line: 3 = (-1/6)*3 + b
This simplifies to: 3 = -1/2 + b
Then solving for 'b', we get: b = 3 + 1/2 = 3.5
Therefore, the equation of our new line that is parallel to the original line and passes through the point (3,3) is y = -(1/6)x + 3.5.
Learn more about Equation of a parallel line here:
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Semester 1: 78, 91, 88, 83, 94
Semester 2: 91, 96, 80, 77, 88, 85, 92
Which statement about Christopher’s performance is correct?
(1) The interquartile range for semester 1 is greater than the
interquartile range for semester 2.
(2) The median score for semester 1 is greater than the median
score for semester 2.
(3) The mean score for semester 2 is greater than the mean score
for semester 1.
(4) The third quartile for semester 2 is greater than the third
quartile for semester 1.
B. –6x + 6y = 30
C. -6x - 6y = 30
D. 6x - 6y = 30
1 - 4i
-3
5
1 + 4i
Answer:
The answer would be 5!
Step-by-step explanation:
You start with 1+2i and the conjugate of this would be 1-2i!
After that, in order to find the product, you multiply (1+2i)(1-2i)
You can use distribution or you can use the formula (a+b)(a-b)=a^2-b^2
Either way the answer will be 1-4i^2
i^2=-1 so you replace the i^2 in our equation with negative 1 and solve to get 5!
Hope this helped! <3
Answer:
x = 26
Step-by-step explanation:
68=x +(16+x) and if you plug in 26 it is 68