42
Solve the equation: 8 =
a) z = 10
b) z = 44
c) z=3
d) z=7

Answers

Answer 1

Answer:

Step-by-step explanation:

the question isn't complete

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A committee at the College Board has been asked to study the SAT math scores for students in Pennsylvania and Ohio. A sample of 45 students from Pennsylvania had an average score of 580, whereas a sample of 38 students had an average score of 530. The sample standard deviations for Pennsylvania and Ohio are 105 and 114 respectively. Does the study suggest that the SAT math score for students in Pennsylvania and Ohio differ

Answers

Answer:

Step-by-step explanation:

From the given information:

The null hypothesis and the alternative hypothesis can be computed as:

$H_0 :\mu_1 -\mu_2 = 0$ (i.e. there is no difference between the SAT score for students in both locations)

$H_1 :\mu_1 -\mu_2 \geq0$ (i.e. there is a difference between the SAT score for students in both locations)

The test statistics using the students' t-test for the two-samples; we have:

$t = \frac{\overline x_1 -\overline x_2}{\sqrt{(s_1^2)/(n_1)+(s_2^2)/(n_2) } }$

$t = \frac{580 -530}{\sqrt{(105^2)/(45)+(114^2)/(38) } }$

$t = \frac{50}{\sqrt{(11025)/(45)+(12996)/(38) } }$

$t = (50)/(√(245+342 ) )$

$t = (50)/(√(587) )$

$t = (50)/(24.228)$

t = 2.06

degree of freedom = ( $n_1 + n_2$ ) -2

degree of freedom = (45+38) -2

degree of freedom = 81

Using the level of significance of 0.05

Since the test is two-tailed at the degree of freedom 81 and t = 2.06

The p-value = 0.0426

Decision rule: To reject $H_o$ if the p-value is less than the significance level

Conclusion: We reject the $H_o$ , thus, there is no sufficient evidence to conclude that there is a significant difference between the SAT math score for students in Pennsylvania and Ohio.

Over three days I earn 2568. On the first day I made twice as much as the second day. On the third day I made three times as much as the second day. How much did I earn on the first day.

Answers

Answer:

I earned $856 on the first day

Step-by-step explanation:

Let's call

x = earning on the second day

2x = earnings on the first day

3x = earnings on the third day

The total earnings are $2568, thus

x + 2x + 3x = 2568

Simplifying:

6x = 2568

Dividing by 6:

x = 2568/6

x = 428

I earned $428 on the second day.

2x = 2*$428 = $856

I earned $856 on the first day

a rectangular parking lot has length that is greater than the width the area of the parking lot is 160 square yards find the length and the width use formula area=length*width the parking lot length

Answers

let 'w' represent the width of the parking lot, then 'w+6' represents its length

area = width * length

160 = w * (w+6)

solving for 'w' we have a positive value of w=10

10+6=16

the width of the parking lot is 10 yards, the length of the parking lot is 16 yards

Final answer:

To find the length and width of a rectangular parking lot given its area, we can use the formula Area = Length * Width. We can set up an equation using this formula and solve for the length and width by factoring or using the quadratic formula.

Explanation:

To find the length and width of the rectangular parking lot, we can use the formula for the area of a rectangle: Area = Length * Width. We are given that the area is 160 square yards. Let's assume the width of the parking lot is x yards. Since the length is greater than the width, we can say that the length is x + k yards, where k is some positive value.

Substituting the values into the formula, we get:
160 = (x + k) * x

To solve for x, we can rearrange the equation into a quadratic equation:
x^2 + kx - 160 = 0

This equation can be factored or solved using the quadratic formula to find the values of x and k, which represent the width and length of the parking lot, respectively.

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2Select the correct answer.
Which value is needed to determine a confidence interval for a sample mean?
OA
the margin of error for the proportion
ов.
the population size
OC.
the sample proportion
OD
the standard error of the mean

Answers

The value needed to determine a confidence interval for a sample mean is the standard error of the mean option (D) is correct.

What is a confidence interval for population standard deviation?

It is defined as the sampling distribution following an approximately normal distribution for known standard deviation.

The formula for finding the confidence interval for population standard deviation as follows:

$\rm s\sqrt{(n-1)/(\chi^2_(\alpha/2, \ n-1))} < \sigma < s\sqrt{(n-1)/(\chi^2_(1-\alpha/2, \ n-1))}$

Where s is the standard deviation.

n is the sample size.

$\chi^2_(\alpha/2, \ n-1) and \chi^2_(1-\alpha/2, \ n-1)$ are the constant based on the Chi-Square distribution table:

α is the significance level.

σ is the confidence interval for population standard deviation.

Calculating the confidence interval for population standard deviation:

We know significance level = 1 - confidence level

It is given that:

The value needed to determine a confidence interval for a sample mean is the standard error of the mean.

CI = X + Z(s/√n)

Here CI is the confidence interval

Z is the confidence level

X is the sample mean

Thus, the value needed to determine a confidence interval for a sample mean is the standard error of the mean option (D) is correct.

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Answer:

D.thestandarderrorofthemean

Step-by-step explanation:

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For every 2 books that Tom buys, he can buy 3 magazines. If he pays $60 fo 4 books and 4 magazines, how much does he have to pay for each book?