Answer:
A x< of 6
Step-by-step explanation:
Answer:
The solution is represented by the first number line, wich has the solutions x=-6 and x=-2.
Step-by-step explanation:
We have an absolute value function for the equation. This means that we should have two differents solution in the real number line. As the equation is
when we clear out the absolute value, we will have two possible solutions:
and
now we clear x from both equations
Then, we have that x=-2 and x=-4 are the solutions for the equation, and therefore the number line that represents the solution is the first one, where the points -6 and -2 are highlighted.
the first number line
given | x + 4 | = 2
removing the bars from the absolute value gives
x + 4 = 2 or x + 4 = - 2
x = 2 - 4 or x = - 2 - 4
x = - 2 and x = - 6 ← solutions
these are indicated on the number line by a solid circle at - 2, - 6
Hello!
Answer:
Step-by-step explanation:
We want that the fractions 3/11 and 1/4 have a common denominator.
Let's find the LCM (least common multiple) of 4 and 11:
So the LCM of 4 and 11 is 44.
Convert fractions over 44:
Answer:
A/5%=b-c+3-5%=d£&68+7-7'
9514 1404 393
Explanation:
a) The velocity curve is linearly increasing from 0 to 6 m/s over a period of 2 seconds, then linearly decreasing from 6 m/s to 0 over the same period. The acceleration is the rate of change of velocity, so for the first half of the motion the acceleration is a constant (6 m/s)/(2 s) = 3 m/s². Similarly, over the second half of the motion, the acceleration is a constant (-6 m/s)/(2 s) = -3 m/s².
The distance traveled is the integral of the velocity, so the linearly increasing velocity will cause the distance vs. time curve to have a parabolic shape. The shape will likewise be parabolic, but with decreasing slope, as the velocity ramps down to zero. Overall, the distance versus time curve will have an "S" shape.
The motion (position and velocity) will be continuous, but the acceleration will not be. There will be a significant "j.erk" at the 2-second mark where acceleration abruptly changes from increasing the velocity to braking (decreasing the velocity).
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b) The attachment shows the (given) velocity curve in meters per second and its integral, the position curve, in meters.
The integral in the attached works nicely for machine evaluation. For hand evaluation, it is perhaps best written piecewise:
(4, −5)
and passes through
(7, 4)
Answer:
Step-by-step explanation:
The equation of a circle of radius r, centered at the point (a,b) is
We already know the center is at , we are just missing the radius. To find the radius, we can use the fact that the circle passes through the point (7,4), and so the radius is just the distance from the center to this point (see attached image). So we find the distance by using distance formula between the points (7,4) and (4,-5):
radius
And now that we know the radius, we can write the equation of the circle: