Answer:
The mass of the dog food added is 9.03 kg
Explanation:
Given;
mass of the shopping cart, m₁ = 14.5 kg
let the mass of the bag added = m₂
the force applied, F = 12 N
initial velocity of the cart-bag system, u = 0
distance traveled by the system, d = 2.29 m
time of motion of the system, t = 3.0 s
The acceleration of the system is calculated as;
The total mass of the system (M) is calculated as follows;
F = Ma
M = F/a
M = (12)/(0.51)
M = 23.53 kg
The mass of the dog food added is calculated as;
m₂ = M - m₁
m₂ = 23.53 kg - 14.5 kg
m₂ = 9.03 kg
Answer:4500 N
Explanation:
Given
mass of truck
mass of car
as the car push the ground with a force of 4500 N so the force on the truck should also be 4500 N as they all the force is transmitted to push the truck
and their acceleration is
Based on Newton's third law of motion, if the car is pushing against the ground with a force of 4500N, that same force is what propels the car and any object attached to it, regardless of the object's mass. Therefore, the car also applies a force of 4500N to the truck it is pushing.
The magnitude of force that a 1200-kg car applies to a 2100-kg truck with a dead battery can be calculated using the principles of Newtons's third law of motion which states that for every action there is an equal and opposite reaction. The force exerted by the car on the ground is equal to the force exerted by the ground on the vehicle. If the car's driving force against the ground is 4500N, as per Newton's third law, the ground also pushes the car back with the same force of 4500N. This force is what propels the car and any object it's connected with.
So, when the car is pushing this truck, it applies this same force of 4500N to the truck. Therefore, the magnitude of force the car applies to the truck is 4500N.
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Answer:
It's C. Grasslands
Explanation: hope it helps ^w^