Answer:
A. reactivity
Explanation:
how a person reacts to the things they use will demonstrate who they are
C Gulf of Baja
b. Pacific Ocean
d. Gulf of Mexico
Answer:
A:Gulf of california
i think that is your answer
Explanation:
Mexico is bounded to the north by the United States (specifically, from west to east, by California, Arizona, New Mexico, and Texas), to the west and south by the Pacific Ocean, to the east by the Gulf of Mexico, and to the southeast by Belize,Guatemala, and the Caribbean Sea.
b. tourist attractions
c. extensive in-migration from nearby areas
d. many. sacred sites
e. high-quality agricultural land
The Nile River valley has the greatest concentration of population in Egypt because of its high-quality agricultural land. Thus, option E is correct.
Eastern Africa is traversed by the Nile River as it travels north to south. It is one of the longest rivers in the world, starting in the rivers that empty into Lake Victoria (found in present-day Uganda, Tanzania, and Kenya) and flowing more than 6,600 kilometers (4,100 miles) to the north to the Mediterranean Sea. Ancient Egypt's development depended heavily on the Nile River.
Due to the significant silt deposits the Nile River leaves behind as it flows into the Mediterranean Sea, the soil of the Nile River delta between El Qâhira (Cairo) and the sea is fertile and full of nutrients. Due to yearly floods that deposit silt, the banks of the Nile are covered in fertile soil throughout much of its length.
Therefore, option E is the ideal selection.
Learn more about the Nile River here:
#SPJ3
Answer:
probably E that's what I would go with
To calculate the noon sun's angle above the horizon at Placerita Canyon, identify today's date and find the corresponding solar declination using the analemma. Next, calculate the arc distance (AD) by subtracting this declination from 34°N, and finally subtract the AD from 90° to get the solar altitude (SA). This gives you the sun's angle above the horizon at noon.
To calculate the angle of the noon sun above the horizon at a location of approximately 34°N latitude, given that the solar altitude (SA) is 90º minus the arc distance (AD). Start with the latitude of 34°N. Identify today's date and find the corresponding declination of the sun using the analemma. Subtract this value from 34°N (or vice versa depending on which is greater) for the AD. Finally, subtract the AD from 90° to get the SA.
For example, if today's declination of the sun was 23°N: AD = 34°N - 23°N = 11°, then SA = 90º - 11º = 79º. So, at noon the sun would be 79 degrees above the horizon at Placerita Canyon if today's date corresponds to a declination of 23°N.
#SPJ2
Answer:
The latitude at which the noon sun is directly overhead is defined as the sun's declination. For example, if the sun appears directly overhead at 20°N latitude, the sun's declination is thus 20°N. Figure 7-3, known as analemma, shows the declination of the sun throughout the year. Thus, if you would like to know where the sun will be directly overhead on September 20, you can look on the analemma and find that it will be at 1°N. Given the declination, the noon sun angle at a particular latitude on any given day can be calculated.
Figure 7-3. The analemma, a graph illustrating the latitude of the overhead noon sun throughout the year.
Figure 7-4 shows that for each degree of latitude that the place is away from the latitude where the noon sun is overhead (declination), the angle of noon sun becomes one degree lower from being vertical (or 90°) above the horizon. Noon sun angle for any given latitude on any given day can be calculated using the following equation:
Noon Sun Angle = 90° - (Latitude +/- Declination)
In this equation, use " - " when the latitude and declination are on the same hemisphere and use " + " when they are on the opposite hemispheres. For example, on April 11, the declination is 8°N, the noon sun angle at Springfield, Illinois (40N) on April 11, therefore, should be 58° (90° - (40°N - 8°N).
Figure 7-4. Noon sun angle calculation. The example in this figure illustrates how to calculate the noon sun angle for a city 40° north of the equator (like Springfield, Illinois) on December 22.
Questions
Based on Figure 7-3, the sun shifts its position between which two important latitudes (find the terminologies for these two latitudes in Fig. 7-4). (2 points)
Using the analemma (Fig. 7-3), determine the declinations on each of the following dates. (6 points)
August 10 _________________
September 21 _______________
June 21 ______________
October 15 ____________
December 22 ______________
March 21 _________________
Calculate the noon sun angle in Grayslake, Illinois on each of the dates listed below. (6 points)
Noon Sun Angle in Grayslake on
August 10 _________________
September 21 _______________
June 21 ______________
October 15 ____________
December 22 ______________
March 21 _________________
Obtain the average temperature in Grayslake on each of the dates listed below using a weather station online. (6 points)
Average Temperature in Grayslake on:
August 10 ________________
September 21 _______________
June 21 _____________
October 15 ____________
December 22 ______________
March 21 _________________
Plot the noon sun angle and temperature on each of the dates you obtained in Questions 3-4 on the graph provided below and connect your temperature and noon sun angle plots using smooth lines. Discuss the relationship between noon sun angles and average temperature in Grayslake throughout the year based on your graph. Use the right vertical axis to show temperature variation from -30° F at bottom and +105° F on top (label temperature value at equal amount interval in between: 2 units for every 5°F). Use the left vertical axis to show noon sun angle, with 0° at the bottom and 90°F on top (label noon sun angle value at equal amount intervals in between: every 3 units per 10°). (4 points)
J F M A M J J A S O N D
Months
Figure 7-5. Variation of temperature and noon sun angle in Grayslake.
brief paragraph summarizing the yearly movement of the overhead noon sun and how the intensity of insolation aries in Grayslake throughout the year. (2 points)
Calculate the maximum, minimum, and average noon sun angles at the place in Grayslake. Show your calculations. (3 points)
Maximum noon sun angle:
Minimum noon sun angle:
Average noon sun angle:
When the noon sun is directly overhead a ship in the Pacific Ocean on October 16, the ship's latitude is _____________. Explain your answer. (2 points)
Answer and Explanation:
Sedimentary structures can decide the paleo current bearing of the antiquated past. Those can be decide by the assistance of structures like current sheet material, separating lineation and so on.
It can decide the paleo stream system condition. At lower stream system we discover structures like wave, hill and so on. At higher stream system we discovered enemy of ridge, separating lineation and so on.
It helps to determine whether the bed is older or younger. Suppose you are getting a sole marking structure. It found at the base of the bed. So where there is a sole marking we can able to tell the top bed is younger.
The prepositional condition can be known like whether it was earthbound or marine. Marine condition will indicate limestone store though earthbound shows sandstone store.
Tells about the marine offense and relapse condition. Offense shows fining upward succession though relapse shows coarsening upward grouping.
Answer:
Option (1)
Explanation:
Isohyets- This are the lines that connects the points of equal amount of rainfall that occurs at any given period of time.
Contour lines- This are the lines of equal elevation.
Isotherms- This are the lines that connects the points of equal temperature.
Isobars- This are the lines connecting the points of equal atmospheric pressure.
Isogrids- This are a type of half hollowed-out structure that is created mostly from a single metallic type of plate with hard triangular rib like structures that are commonly known as stringers. This are very light and hard in comparison to other substances, This are very costly to build, so they are basically used for the applications that are usually related to the spaceflight and also used in the field of aerospace.
Thus, the isogrids are not a common type of isoline.
Hence, the correct answer is option (1).