At noon the temperature was -4° C. Over the next two hours the temperature dropped another 11 degrees. Then every hour until 7:00 the temperature rose 3 degrees. What was the temperature at 7:00

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Answer 1

Answer: I think it’s 0 degrees

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What is the least common multiple of 17 and 23

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Least common multiple (LCM) of 17 and 23 is 391.

LCM = 17 x 23 = 391

I need some help pretty please!

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Answer:

Number & Cost($)

Feet & Yards

Step-by-step explanation:

Number & Cost:

(2, 38), (4, 76) <====== pick any two point to find constant

constant = (y₂ - y₁) / (x₂ - x₁)

= (76 - 38) / (4 - 2)

= 38 / 2

= 19 <====== k the constant

y = kx

y = 19x

point (2, 38): 38 = 19(2) ===> 38 = 38

point (4, 76): 76 = 19(4) ===> 76 = 76

point (7, 133): 133 = 19(7) ===> 133 = 133

point (9, 171): 171 = 19(9) ===> 171 = 171

Feet & Yards:

(27, 9), (75, 25) <====== pick any two point to find constant

constant = (y₂ - y₁) / (x₂ - x₁)

= (25 - 9) / (75 - 27)

= 16 / 48

= 1/3 <====== k the constant

y = kx

y = 1/3x

point (3, 1): 1 = 1/3(3) ===> 1 = 1

point (12, 4): 4 = 1/3(12) ===> 4 = 4

point (27, 9): 9 = 1/3(27) ===> 9 = 9

point (75, 25): 25 = 1/3(75) ===> 25 = 25

A light-year is a unit used to measure large distances in space. One light-year is approximately equal to 5.88 trillion miles. On a map of the Milky Way Galaxy, the scale is 1 inch:70 light-years. If two stars on the map are 19 inches apart, about how far apart are they in the galaxy?

Answers

Answer:

$7.8204* 10^(15)\ \text{miles}$

Step-by-step explanation:

In the map the scale is

$1\ \text{inch}=70\ \text{light-years}$

$19\ \text{inches}=19* 70=1330\ \text{light-years}$

In miles

$1\ \text{light-year}=5.88* 10^(12)\ \text{mi}$

$1330\ \text{light-years}=1330* 5.88* 10^(12)=7.8204* 10^(15)\ \text{miles}$

The galaxies are $7.8204* 10^(15)\ \text{miles}$ apart.

Pls pls help me bro i’m abt to fail

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10 hours babysitting and 3 tutoring

1 . The lengths of the legs of a right triangle are 25 cm and 60 cm. What is the length of the hypotenuse?
A. 42.5 centimeters
B. 65 centimeters
C. 9.2 centimeters
D. 35 centimeters

D.

35 centimeters

Answers

$a^(2)+ b^(2) = c^(2)$ that is, hypotenuse.
Therefore, let the length of the hypotenuse be 'x.'
$25^(2)+ 60^(2)= x^(2)$
625+3600= $x^(2)$
4225= $x^(2)$
Therefore,
$√(4225)$ =x
65=x
The length of the hypotenuse is B.65 centimetres.

Which of the following gives an example of a set that is closed under multiplication? Choose all that apply.. . . . A. The product of a perfect cube and a perfect cube. B. The product of 0 and 0. C. The product of a whole number and a whole number. D. The product of a perfect square and a perfect square. . I think its b and c? help anyone...

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All the four choices that are given in the question can be considered as as examples of a set that is closed under multiplication. The correct options among all the options that are given in the question are options "A", "B", "C" and "D". I hope that the answer has come to your help.