(6)and-
The terms of an expression 4x² – 3xy are:
(a) 4x and -3xy (b) 4x² and 3xy
(c) 4x² and -xy
(d) x

Answers

Answer 1

Answer:

Answer:

(b) 4x² and 3xy

Step-by-step explanation:

The terms of an expression 4x² – 3xy are:

The terms are the factors of the expression, which are 4x² and -3xy. The signal is not counted as a term. So the correct answer is given by option b.

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23.5 in expanded form164.38 in expanded form
209.106 in expanded form

can you help me

Answers

Answer:

+ 3

+ 0.5

100

+ 60

+ 4

+ 0.3

+ 0.08

200

+ 0

+ 9

+ 0.1

+ 0.00

+ 0.006

Step-by-step explanation:

Hope this helps :D

Answer:

23.5 in expanded form is: 20 + 3 + 0.5

164.38 in expanded form is: 100 + 60 + 4 + 0.3 + 0.08

209.106 in expanded form is: 200 + 0 + 9 + 0.1 + 0.00 + 0.006

Step-by-step explanation:

Show the value of each digit when writing in expanded form. Use plus signs (+) between the values. Knowing the definition of expanded notation can help. Expanded notation means:

"Writing a number to show the value of each digit. It is shown as a sum of each digit multiplied by its matching place value (ones, tens, hundreds, etc.)."

You want to rent an unfurnishedone-bedroomapartment for next semester. The mean monthlyrent for a random
sample of 10 apartments advertised in the localnewspaper is $580.
Assume that the standard deviation is$90. Find a 95% confidence
interval for the mean monthly rentfor unfurnished one bedroom
apartments available for rent in thiscommunity.

Answers

Answer: $(\$524.22,\ \$635.78)$

Step-by-step explanation:

Confidence interval for population mean is given by :-

$\overline{x}\pm z^* (\sigma)/(√(n))$

, where $\overline{x}$ = Sample mean

z* = critical z-value.

$\sigma$ = Population standard deviation.

n= Sample size.

Let x be the denotes the monthly rent for unfurnished one bedroom apartments available for rent in this community.

As per given , we have

n= 10

$\overline{x}=\$580$

$\sigma=\$90$

Critical value for 95% confidence : z* = 1.96

So the 95% confidence interval becomes,

$580\pm (1.96) (90)/(√(10))$

$=580\pm (1.96) (90)/(3.162278)$

$=580\pm (1.96)(28.46)$

$=580\pm 55.78$

$=(580-55.78,\ 580+55.78)=(524.22,\ 635.78)$

Hence, a 95% confidence interval for the mean monthly rent for unfurnished one bedroom apartments available for rent in this community= $(\$524.22,\ \$635.78)$

A researcher wishes to estimate the proportion of adults who have high-speed Internet access. What size sample should be obtained if she wishes the estimate to be within 0.03 with 90% confidence if (a) she uses a previous estimate of 0.34?(b) she does not use any prior estimates? n=_____(Round up to the nearest integer.)

Answers

Answer:

675 samples

752 samples

Step-by-step explanation:

Given that :

α = 90%

E = 0.03

Previous estimate (p) = 0.34

Estimated sample proportion (n)

n = p *q * (Zcritical /E)

Zcritical = α/2 = (1 - 0.9) /2 = 0.1 / 2 = 0.05

Z0.05 = 1.645 ( Z probability calculator)

q = 1 - p = 1 - 0.34 = 0.66

n = 0.34 * 0.66 * (1.645/0.03)^2

n = 674.70

n = 675

B.) without prior estimate given ;

p and q should have equal probability

Hence ;

p = 0.5 ; q = 0.5

n = 0.5 * 0.5 * (1.645/0.03)^2

n = 751.67361

n = 752

Final answer:

To determine the sample size for the research, a mathematical calculation is required, considering the level of confidence, the desired margin of error, and, if available, a previous estimate. For a 90% confidence level, two calculations are made based on an assumed proportion—first using the existing estimate of 0.34, and second with no prior estimate (commonly taken as 0.5).

Explanation:

The researcher is trying to determine the sample size required for a study on high-speed Internet access. The sample size can be calculated based on the level of confidence desired and the desired margin of error. In this case, (a) she is using a previous estimate of 0.34 and (b) she does not use any prior estimates.

For the calculation, we can use the formula for sample size in hypothesis testing for a population proportion:

n = (Z^2 * p * (1-p)) / E^2

Where:

n = required sample size
Z = z-score corresponding to our desired level of confidence
p = assumed proportion (in part (a) this is 0.34)
E = desired margin of error

For a 90% confidence level, the corresponding z-score is approximately 1.645. Now we can plug in the numbers.

(a) If she uses a previous estimate of 0.34, the calculation would be:

n = (1.645^2 * 0.34 * 0.66) / (0.03)^2

You will need to round up to the nearest whole number as you cannot have a part of a participant.

(b) If no previous estimate is used, it is common practice to use 0.5 as this will provide the maximum variance and, therefore, the largest sample size. The calculation would be:

n = (1.645^2 * 0.5 * 0.5) / (0.03)^2

Again, round up to the next whole number. Insert the results for these calculations to your answer.

Learn more about Sample Size Calculation here:

brainly.com/question/33689461

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Determine from the balanced chemical reaction ifthe derived mole ratio is correct or incorrect.

Answers

It's incorrect. There are 6 moles of NaBr produced for every 3 moles of Na₂S among the reactants (as well as 2 moles of FeBr₃), so the mole ratio of NaBr to Na₂S should be 2 : 1, not 1 : 1.

Given the function and the graph below, please answer the following: