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12% of students of a class of 50 like blue
colour. How many children like blue colour?

Answers

Answer 1

Answer:

If 12% of students of a class of 50 like blue colour, the number of children that like blue is 6

The number of students in the class = 50

12% of the total number of students like blue

Number of students that like blue colour = 12% of 50

Number of students that like blue colour = (12/100) x 50

Number of students that like blue colour = 0.12 x 50

Number of students that like blue colour = 6

Therefore, if 12% of students of a class of 50 like blue colour, the number of children that like blue is 6

Learn more here: brainly.com/question/22055494

Answer 2

Answer:

Answer:

6 children

Step-by-step explanation:

(12*50)/100

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A number, n, is multiplied by -3/8. The product is -0.5 What is the value of n?
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An ice cream cone is filled with vanilla and chocolate ice cream at a ratio of 2:1. If the diameter of the cone is 2 inches and the height is 6 inches, approximately what is the volume of vanilla ice cream in the cone? (round to nearest tenth) A) 1.0 in3 B) 2.1 in3 C) 4.2 in3 D) 6.3 in3

Answers

Answer:

D. 6.3 in^3

Step-by-step explanation:

V= 1/3 (3.14)(r^2)(h)

V= 1/3 (3.14) (1^2)(6)

V=6.3 in^3

Answer:

Step-by-step explanation: it was on usa test prep and the answer that was there was wrong.

Brandon wants to use the Distributive Property to figure this problem out. What should be his next step?Brandon's step so far: 8 × (10 + 7)

(8 × 10) + (8 × 7)
(8 + 10) × (8 + 7)
(8 × 10) + 7
10 + (8 × 7)

Answers

His next step would be:

(8 x 10) + (8 x 7)

Why?
Because when using the distributive property, you distribute the number outside of the parentheses to the numbers inside the parentheses, and in this case, we are multiplying so you will multiply 8 by both 10, and 7.

Hope this helps!
If you have any further questions just ask me in the comments!

If f(x) = 2x – 5 and g(x) = x +4, then f(g(2)) =

Answers

Answer:

Step-by-step explanation:

f(g(2))

f(x+4) and you would replace x with two, so you would get

f(2+4) = f(6)

You would then plug in 6 for the x in the f(x) equation:

2(6) - 5 = 12-5 = 7

Is 16-7=4+5 true, false, or open?

Answers

Answer:

open

Step-by-step explanation:

Answer:

This is True.

Step-by-step explanation:

16-7=9

5+4=9

same ting

Determine whether the improper integral converges or diverges, and find the value of each that converges.∫^0_-[infinity] 5e^60x dx

Answers

Answer:

The improper integral converges.

$\displaystyle \int\limits^0_(- \infty) {5e^(60x)} \, dx = (1)/(12)$

General Formulas and Concepts:
Calculus

Limit

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_(x \to c) x = c$

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle (d)/(dx) [cf(x)] = c \cdot f'(x)$

Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = (x^(n + 1))/(n + 1) + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Method: U-Substitution

Improper Integral: $\displaystyle \int\limits^(\infty)_a {f(x)} \, dx = \lim_(b \to \infty) \int\limits^b_a {f(x)} \, dx$

Step-by-step explanation:

Step 1: Define

Identify.

$\displaystyle \int\limits^0_(- \infty) {5e^(60x)} \, dx$

Step 2: Integrate Pt. 1

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^0_(- \infty) {5e^(60x)} \, dx = 5 \int\limits^0_(- \infty) {e^(60x)} \, dx$
[Integral] Rewrite [Improper Integral]: $\displaystyle \int\limits^0_(- \infty) {5e^(60x)} \, dx = \lim_(a \to - \infty) 5 \int\limits^0_(a) {e^(60x)} \, dx$

Step 3: Integrate Pt. 2

Identify variables for u-substitution.

Set u: $\displaystyle u = 60x$
[u] Differentiate [Derivative Properties and Rules]: $\displaystyle du = 60 \ dx$
[Bounds] Swap: $\displaystyle \left \{ {{x = 0 \rightarrow u = 0} \atop {x = a \rightarrow u = 60a}} \right.$

Step 4: Integrate Pt. 3

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^0_(- \infty) {5e^(60x)} \, dx = \lim_(a \to - \infty) (1)/(12) \int\limits^0_(a) {60e^(60x)} \, dx$
[Integral] Apply Integration Method [U-Substitution]: $\displaystyle \int\limits^0_(- \infty) {5e^(60x)} \, dx = \lim_(a \to - \infty) (1)/(12) \int\limits^0_(60a) {e^(u)} \, du$
[Integral] Apply Exponential Integration: $\displaystyle \int\limits^0_(- \infty) {5e^(60x)} \, dx = \lim_(a \to - \infty) (1)/(12) e^u \bigg| \limits^0_(60a)$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^0_(- \infty) {5e^(60x)} \, dx = \lim_(a \to - \infty) (1 - e^(60a))/(12)$
[Limit] Evaluate [Limit Rule - Variable Direct Substitution]: $\displaystyle \int\limits^0_(- \infty) {5e^(60x)} \, dx = (1 - e^(60(-\infty)))/(12)$
Rewrite: $\displaystyle \int\limits^0_(- \infty) {5e^(60x)} \, dx = (1)/(12) - (1)/(12e^(60(\infty)))$
Simplify: $\displaystyle \int\limits^0_(- \infty) {5e^(60x)} \, dx = (1)/(12)$

∴ the improper integral equals $\displaystyle \bold{(1)/(12)}$ and is convergent.

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Learn more about improper integrals: brainly.com/question/14413972

Learn more about calculus: brainly.com/question/23558817

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Topic: AP Calculus BC (Calculus I + II)

Unit: Integration

Answer:

$\int_(-\infty)^0 5 e^(60x) dx = (1)/(12)[e^0 -0]= (1)/(12)$

Step-by-step explanation:

Assuming this integral:

$\int_(-\infty)^0 5 e^(60x) dx$

We can do this as the first step:

$5 \int_(-\infty)^0 e^(60x) dx$

Now we can solve the integral and we got:

$5 (e^(60x))/(60) \Big|_(-\infty)^0$

$\int_(-\infty)^0 5 e^(60x) dx = (e^(60x))/(12)\Big|_(-\infty)^0 = (1)/(12) [e^(60*0) -e^(-\infty)]$

$\int_(-\infty)^0 5 e^(60x) dx = (1)/(12)[e^0 -0]= (1)/(12)$

So then we see that the integral on this case converges amd the values is 1/12 on this case.

Write code to complete doublepennies()'s base case. sample output for below program: number of pennies after 10 days: 1024 note: these activities may test code with different test values. this activity will perform three tests, with starting pennies = 1 and userdays = 10, then with starting pennies = 1 and userdays = 40, then with startingpennies = 1 and userdays = 1. see how to use zybooks. also note: if the submitted code has an infinite loop, the system will stop running the code after a few seconds, and report "program end never reached." the system doesn't print the test case that caused the reported message.

Answers

answer with coding and answer is attached in word file below

The doublePennies() function is an illustration of a recursive function in Java

How to complete the doublePennies() function?

The base case of the doublePennies() function is that:

When the number of days is 0, then the total available pennies is the same as the total number of pennies.

The algorithm of the above highlight is:

if numDays equals 0 then

totalPennies = numPennies

Using the above algorithm, the complete base case is:

if(numDays == 0){

totalPennies = numPennies;

}

12% of students of a class of 50 like bluecolour. How many children like blue colour?​

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How to complete the doublePennies() function?

12% of students of a class of 50 like blue
colour. How many children like blue colour?