Answer:
Initial value is (0 , 24) or just y = 24
Step-by-step explanation:
Initial value of a linear function is the y intercept
y = -3x + 24
x = 0, y = 24
B. 6,176 gallons
C. .886 gallons
D. 23,400 gallons
we know that
approximate
so
by proportion
therefore
the answer is the option A
The number of gallons of water that the water tank can hold, given the cubic meters is A. 61,776 gallons.
In the US customary measurement system, 1 cubic meter is approximately equal to 264.172 gallons.
Therefore, a water tank that holds 234 cubic meters can hold approximately:
= 234 cubic meters * 264.172 gallons/cubic meter = 61,808 gallons.
The closest option would be A. 61,776 gallons
Find out more on gallons at brainly.com/question/26259781
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G.y=-1/8x-63/8
h.8x-9
J.y=1/8X+585/8
2k(7-5k)+11=6k+3(k^2-1)
with work please.
Answer:
Step-by-step explanation:
2k(7-5k)+11=6k+3(k^2-1)
We move all terms to the left:
2k(7-5k)+11-(6k+3(k^2-1))=0
We add all the numbers together, and all the variables
2k(-5k+7)-(6k+3(k^2-1))+11=0
We multiply parentheses
-10k^2+14k-(6k+3(k^2-1))+11=0
We calculate terms in parentheses: -(6k+3(k^2-1)), so:
6k+3(k^2-1)
We multiply parentheses
3k^2+6k-3
Back to the equation:
-(3k^2+6k-3)
We get rid of parentheses
-10k^2-3k^2+14k-6k+3+11=0
We add all the numbers together, and all the variables
-13k^2+8k+14=0
a = -13; b = 8; c = +14;
Δ = b2-4ac
Δ = 82-4·(-13)·14
Δ = 792
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
k1=−b−Δ√2ak2=−b+Δ√2a
The end solution:
Δ−−√=792−−−√=36∗22−−−−−−√=36−−√∗22−−√=622−−√
k1=−b−Δ√2a=−(8)−622√2∗−13=−8−622√−26
k2=−b+Δ√2a=−(8)+622√2∗−13=−8+622√−26