How far is the star away from the earth in AU?
How far is the star away from the earth in - 1

Answers

Answer 1
Answer:

Final answer:

The average distance between a star and Earth is typically measured in astronomical units (AU), which is the average distance between Earth and the Sun. To calculate the distance in AU, divide the star's distance in kilometers or miles by the average distance between Earth and the Sun.

Explanation:

The average distance from the Earth to a star is typically measured in astronomical units (AU). An astronomical unit is defined as the average distance between the Earth and the Sun, which is about 149.6 million kilometers or 93 million miles.

To calculate the distance to a star in AU, you need to determine the star's distance in kilometers or miles and then convert it to AU. For example, if a star is 900 million kilometers away, you divide that distance by the average distance between the Earth and the Sun to get the distance in AU. In this case, the star would be approximately 6 AU away from Earth.

It's important to note that the distances between stars and Earth are incredibly vast, so even a distance of a few AU is still very far.

Learn more about Distance between stars and Earth here:

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-7+6(n-1) find the fourth term

Answers

Answer:

11

Step-by-step explanation:

To find the 4th term, you simply put 4 in for n because n denotes which term:

-7+6(n-1)=-7+6(4-1)=-7+6*3=-7+18=11

The answer is thus 11.

3 − 8 x = 8 5 x , written as a decimal

Answers

Answer:

5/16

Step-by-step explanation:

X+2y=14
x-3y=-11
substitution

Answers

To solve this system of equations using substitution, we can solve one equation for one variable and substitute it into the other equation. Let's solve the first equation for x:

x = 14 - 2y

Now, substitute this expression for x in the second equation:

(14 - 2y) - 3y = -11

Simplify the equation:

14 - 2y - 3y = -11

Combine like terms:

14 - 5y = -11

Now, solve for y:

-5y = -11 - 14

-5y = -25

y = -25 / -5

y = 5

Now, substitute the value of y back into the first equation to solve for x:

x + 2(5) = 14

x + 10 = 14

x = 14 - 10

x = 4

So, the solution to the system of equations is x = 4 and y = 5.
Consider brainliesttt

Find the area and the circumference of a circle with diameter 5 cm.Use the value 3.14 for it, and do not round your answers. Be sure to include the correct units in your answers.

Answers


The Circumference of the circle is
15.7

and Area is
19.625

Help ASAP Science/ Math..... Bill and Amy want to ride their bikes from their neighborhood to school which is 14,400 meters away. It takes Amy 2400 seconds to arrive at school. Bill arrives 1200 seconds after Amy. How much faster (in meters/ seconds) is Amy's average speed for the trip?

Answers

Answer:

Amy is 1200 seconds fater than Bill.

Step-by-step explanation:

A soup can in the shape of a right circular cylinder is to be made from two materials. The material for the side of the can costs $0.015 per square inch and the material for the lids costs $ 0.027 per square inch. Suppose that we desire to construct a can that has a volume of 16 cubic inches. What dimensions minimize the cost of the can? a. Draw a picture of the can and label its dimensions with appropriate variables.
b. Use your variables to determine expressions for the volume, surface area, and cost of the can.
c. Determine the total cost function as a function of a single variable. What is the domain on which you should consider this function?
d. Find the absolute minimum cost and the dimensions that produce this value.

Answers

Answer:

a) file annex

b) V(c) = π*x²*y

    A(x) = 2*π*x² + 32/x

    C(x) =  0,1695*x²  +  0,48 /x

     Domain C(x) = {x/ x >0}

d) C(min) = 0,64 $

    x = 1.123 in      radius of base

    y = 4,04 in      height of the can

     

Step-by-step explanation:

See annex file

Lets:

call x = radius of the base of the cylinder  and

y = the height of the cylinder

Then

Volume of the cylinder      ⇒    V(c) =  π*r²*h             ⇒V(c) = π*x²*y

And  y = V / ( π*x²)     ⇒   V = 16 / ( π*x²)

Area of cylinder  = lids area  +  lateral area

lids area = 2*π*x²  ⇒  lateral area = 2*π*x*y

lateral area =2*π*x [16/(π*x²) ]    ⇒   lateral area =  32/x

Then

A(x) = 2*π*x² + 32/x

Function cost C(x)

C(x) = 0.027 *  2*π*x²  +  0.015 * (32/x)

C(x) =  0,1695*x²  +  0,48 /x

Domain C(x) = {x/ x >0}

Now function cost:

C(x) =  0,1695*x²  +  0,48 /x

Taking derivative:

C´(x) =  2*0,1695*x  - 0.48/x²     C´(x)  =  0,339*x  -  0.48/x²

C´(x)  = 0            0.339*x³ - 0.48 = 0   x³ = 0.48/0.339   x³  = 1.42

x = 1.123 in

y = 16/πx²     ⇒  y = 4,04 in

C(min) = 0,64 $