Answer:
formual is
V = IR
V = 3*15
V= 45 V
hope it helps
Given the current of 3 A and resistance of 15 Ohms, we can use Ohm's Law to calculate the voltage. We rearrange the formula to V = I * R, fill in the given values which results to V = 45 V. The correct answer is A. 45 V.
The problem involves Ohm's Law which is a foundational concept in Physics, particularly in the study of electricity. Ohm's Law states that the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points, and is inversely proportional to the resistance (R). The formula that represents Ohm's Law is I = V/R.
Given the current (I = 3 Amps) and the resistance (R = 15 Ohms), we can rearrange the formula to solve for voltage (V). Thus, the formula becomes V = I * R. When the given values are substituted, we have V = 3 A * 15 Ω, which results in V = 45 V. Therefore, a voltage of 45 V will produce 3 A in a circuit with 15 ohms of resistance. The correct answer is A. 45 V.
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b. 3,000
c. 30,000
d. 300,000
b. -0.037 cm
c. 0.370 cm
d. 0.370 cm
Answer:
Explanation:
y = (0.2 cm) Sin(2x - 3 t + π/16)
Put x = 4 m, t = 10 s
y = (0.2 cm) Sin (2 x 4 - 3 x 10 + π/16)
y = (0.2 cm) Sin (8 - 30 + π/16)
y = (0.2 cm) Sin (π/16 - 22)
y = (0.2 cm) Sin(-21.80375)
y = (0.2 cm) x (- 0.1863)
y = - 0.37 cm
The given wave function represents a transverse wave on a string. Substituting the given values into the wave function yields a height of -0.037 cm. The correct option is a. -0.037 cm.
The given wave function y(x,t) represents a transverse wave on a string. To find the height of the string with respect to the equilibrium position at a position x = 4.00m and a time t = 10.00s, substitute these values into the wave function. y(4.00m, 10.00s) = (0.20 cm) sin[(2.00 m-1)(4.00m) - (3.00 s-1)(10.00s) + π/16].
Calculating this expression gives the height of the string as -0.037 cm. Therefore, the correct option is a. -0.037 cm.
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Answer:
ok
Explanation:
what is the length of the court. you need the length to answer the question
Answer:
False. Opposite electric charges will attract, and like charges will repel.