A car traveled twice as fast on a dry road as it did making the return on a slippery road. the trip was 60 mi each way, and the round trip took 35 hr.

Answers

Answer 1
Answer: If it was 60 miles round trip, each way was therefore 30 miles.
Let x represent the hours taken on the dry road.  Slippery road was then 2x.  2x + x = 3x.  35 / 3 = 11.66… = x.
So, on the dry road, the car took 11.66…  hours.
For the slippery one, 2 * 11.66… or 23.33…  hours.
Convert to mph, shall we?
Dry road:
30 miles / 11.66… hours = 2.57… mph.
Slippery road:
30 miles / 23.33… hours = 1.28… mph.
If that’s what you’re looking for — you never quite asked.

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What is 22/52 reduced into a fraction

Answers

The common factor here is 2, so this reduces to 11/26
Same as the other person said 11/26 because 2 can go into both top and bottom numbers check: 11 x 2= 22 26 x 2 = 52 = 22/52 correct

A piece of equipment is purchased for $18,000.00 and has a salvage value of $2,000.00.The estimated life is then years and the method of depreciation is straight-line. Shipping costs total $620.00 and installation costs are $590.00. The book value at the end of year 10 is....A.)$1,110.00

B)$2,110.00

C)$3,110.00

D)$2,000.04

HEEEELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP!!!! XD

Answers

Hello one of my favvvvv sons!
This is Accounting math, so congrats at being in college level math!
 Now let's solve this!  :)

The Book Value of an asset is the asset's cost minus the assets accumulated depreciation.
 Asset's costs:
           Purchase of equipment =  $18,000
           Shipping costs =  $620.00
           Installation costs =  $590.00
                                    
              Total = $19,210.00

Assets accumulated depreciation:

  depreciation per year=(Cost of equipment-Salvage Value) ÷ Estimated Useful Life = (18000 - 2000) ÷ 10 = $ 1,600 per anum (per year)

           Cost: $18,000
           Salvage Value: $ 2,000
           Estimated Useful Life:  10 years

 With this data, we can make the following chart provided below.
Looking at the chart we can conclude that hence, in the 10th year, the accumulated depreciation value is $ 16,000.

So the Book Value at the end of year 10 is...
an asset is the assets cost - the assets accumulated depreciation.
$19,210.00 - $16,000 = $ 3,210

Hope I helped! If you have any other questions or would like further explanation feel free to Pm me! Have a great day!!! :)

What is the standard form of the parabola whose vertex form is Y=-(X-3)^2+11

Answers

y=-(x-3)^2+11\ny=-(x^2-6x+9)+11\ny=-x^2+6x-9+11\ny=-x^2+6x+2

Good evening guys

I nee your help , can you ?

Answers

5h^3: 5 * h * h * h
20h^2: 2 * 2 * 5 * h * h
GCF(5h^3, 20h^2) = 5h^2

4h: 2 * 2 * h
16: 2 * 2 * 2 * 2
GCF(4h, 16) = 4

The answer is C.

60 is what percent of 72

Answers

If you would like to solve 60 is what percent of 72, you can calculate this using the following steps:

60 is what percent of 72
60 = x% of 72
60 = x% * 72
60 = x/100 * 72
60/72 = x/100
x = 60/72 * 100
x = 83.33%

The correct result would be 83.33%.
60 is 83% of 72.


60 divided by 12 is 5, and 72 divided by 12 is six.
5/6 equals 0.83
0.83 x 100 is 83, or 83%.

Brainiest would be nice.

I sell cookies for $3 and muffins for $7. Yesterday, I made $129. I sold a total of 27 items. How many of each did I sell?

Answers

You sold 15 cookies and 12 muffins.

c - cookies
m - muffins

c + m = 27

3c + 7m = 129

I don’t know how to explain how to do efficiently but I just plugged in numbers until it worked:

3(15) + 7(12) = 129

45 + 84 = 129

Answer:

You sold 15 cookies and 12 muffins

Step-by-step explanation:

So you're given that 1 cookie is sold for $3 and 1 muffin is sold for $7

You're also given that in total you made $129, and sold 27 items

Let's make equations from that, letting c stand for amount of cookies and m for amount of muffins.

  • 3c + 7m = 129 (equation for amount of money made)
  • c + m = 27 (equation for amount of items sold)

Now we can use the second equation to find m:

c + m = 27

m = 27 - c

Not we can substitute m into the first equation to find c:

3c + 7m = 129                  

3c + 7(27-c) = 129            [substitute m for (27-c)]

3c + 189 -7c = 129           [distribute 7 into (27-c)]

-4c + 189 = 129                [combine like terms]

-4c = -60                          [subtract 189 from both sides]

c = 15                               [divide both sides by -4]

Now we can substitute c into the second equation to find m:

c + m = 27

15 + m = 27

m = 12