Mass of a substance = Moles of a substance × molar mass of a substance
We have 0.94 moles of NaHCO3. The molar mass of NaHCO3 is the sum of the atomic masses of the elements comprising NaHCO3, which is approximately 84.007 g/mol.
The mass of 0.94 moles of sodium bicarbonate is therefore (0.94 moles NaHCO3)(84.007 g NaHCO3/mol NaHCO3) = 78.97 ≈ 79 grams of sodium bicarbonate.
The number of liters of a gas that would produced at STP is 121.86 Liters
calculation
Step 1 : calculate the moles of hydrogen chloride gas using ideal gas equation
That is PV=nRT where,
P( pressure) = 5100 mm hg
V(volume)= 20.1 L
n(number of moles)= ? moles
R( gas constant) = 62.3636 L.mmhg/mol.K
T( temperature) =29 °C in to kelvin = 29 +273 =302 K
by making n the subject of the formula by diving both side by RT
n= Pv/RT
n=[(5100 mm hg x20.1 L)/(62.3636 l.mmhg/mol.k x 302 K)] =5.44 moles
Step : calculate the liters of a gas at STP
that is at STP
1 moles = 22.4 L
5.44 moles=? L
by cross multiplication
=( 5.44 mole x 22.4 L) / 1 mole =121.86 liters
I know what you're asking but I don't think the question is stated properly. Technically, an atom will not join with an "oxide" ion; i.e., the oxide ion is an atom of oxygen to which two electrons have been added. An oxide ion will add to 2 K ions or 1 Ca ion. The K ion has lost just one electron so it takes two of them to equal the 2- charge on the oxide ion whereas the Ca ion has lost two electrons and it takes only one of them to equal the charge on the oxide ion.
A. 2PO43–(aq) + Cl– (aq) → Cl2(PO4)3(s)
B. 2Ca2+(aq) + Na+(aq) → NaCa2(s)
C. Na+(aq) + Cl– (aq) → NaCl(s)
D. 2PO43–(aq) + 3Ca2+(aq) → Ca3(PO4)2(s)
Answer:
Explanation:
In net ionic equation we remove the spectator ions. The ions which are present on both the side and are not forming any solid compound.
Let us write the balanced reaction first:
The ionic reaction is:
Thus net ionic reaction is