Answer:
Option A
Step-by-step explanation:
2(x+14)=2x+28
2x+28=2x+28
IT HAS REAL SOLUTION :)
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The required price of the paperback book and hardback book is $2.95 and $13.95 respectively.
Given that,
The cost of a paperback book is 11 dollars less than the cost of a hardback book. Recently one day of sales totaled $784.10. That day the bookstore sold 53 paperback books and 45 hardback book.
Simultaneous linear equations are two- or three-variable linear equations that can be solved together to arrive at a common solution.
Here,
Let the price of paperback be x and price of hardback books be y,
According to the question,
x = y - 11 - - - (1)
53x + 45y = 784.10 - - - (2)
From equation 1
53 [y - 11] + 45y = 784.10
y = $13.95
Now,
y = 13.95 - 11
y = $2.95
Thus, the required price of the paperback book and hardback book is $2.95 and $13.95 respectively.
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2.Calculate the cost of a can of baked beans, a packet of sugar and a packet of biscuits.
3.How much will 8 cans of baked beans,1 packet of sugar and 6 packets of biscuits cost?
Answer:
To compute the length of the curve f(x)=47(4−x2) over the interval 0≤x≤2, we need to use the formula for the arc length of a function:
L=∫ab1+(f′(x))2dx
where a and b are the endpoints of the interval. First, we need to find the derivative of f(x), which we can do by using the chain rule and the power rule:
f′(x)=4dxd7(4−x2)
f′(x)=427(4−x2)1dxd(7(4−x2))
f′(x)=427(4−x2)1(−14x)
f′(x)=−7(4−x2)28x
Next, we need to plug in f′(x) into the formula and simplify:
L=∫021+(−7(4−x2)28x)2dx
L=∫021+7(4−x2)784x2dx
L=∫027(4−x2)7(4−x2)+784x2dx
L=∫024−x228−21x2dx
Now, we need to evaluate the integral, which we can do by using a trigonometric substitution. Let x=2sinu, then dx=2cosudu and u=arcsin(x/2). The limits of integration change as follows:
x=0⟹u=0
x=2⟹u=2π
The integral becomes:
L=∫02π4−(2sinu)228−21(2sinu)2(2cosu)du
L=∫02π4−4sin2u28−84sin2u(2cosu)du
L=∫02π1−sin2u7−21sin2u(2cosu)du
L=∫02πcos2u7−21sin2u(2cosu)du
L=∫02π27−21sin2udu
Using a trigonometric identity, we can write:
L=∫02π4127−1221cos(2u)du
Using another trigonometric substitution, let v=2u, then dv=2du and u=v/2. The limits of integration change as follows:
u=0⟹v=0
u=2π⟹v=π
The integral becomes:
L=∫0π4127−1221cosv(21)dv
L=6∫0π
B. 4 × 5 × 7 × 9
C. 2 × 3 × 5 × 6 × 7
D. 2 × 3 × 5 × 7
Answer:
A.2x2x3x3x5x7
Step-by-step explanation:
Penn foster
a = 10
b = 3
C = 15°
(Hint: c^2 = a^2 +b^2 - 2ab*cos(C) is law of
cosine)
Answer:
Measure of side C is 7.14
Step-by-step explanation:
In this question, we are to find the length of the side C.
To get this, we are to employ the use of the cosine formula.
Mathematically, this is calculated as;
c^2 = a^2 +b^2 - 2ab*cos(C)
Where; a = 10 b = 3 and c = 15 degrees
Plugging these values into the equation, we have;
C^2 = 10^3 + 3^2 -2(3)(10)Cos 15
C^2 = 100 + 9 - 57.96
C^2 = 51.04
C = √(51.04)
C = 7.14
Answer:
7.14
Step-by-step explanation: