What is the value of sin67.5? use half angle formula
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The solution wouldbe like this for this specific problem:
sin(67.5) = sin(135/2)
sin(x/2) = +/- √((1 - cos(x))/√2
sin(67.5) = √(1 - cos(135))/√2 = √(1 + √2/2)/√2 = √(√2/4 + 1/2) = 0.9239
I am hoping thatthis answer has satisfied your query and it will be able to help you in yourendeavor, and if you would like, feel free to ask another question.
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Write the expression that represents the phrase: the quotient of 10 and x
The demand d for a companys product cost x is predicted by the function d(x) = 500-2x. The price p in dollars that the company can charge for the product is given by p(x)=x+5
Raphael paid $160 for a camera during a 75% off sale. What was the camera's regular price?
True or false
Answers
Answer:
False
Step-by-step explanation:
Every rhombus has two diagonals connecting pairs of opposite vertices, and two pairs of parallel sides.
Answers
Answers
Answer:
I believe the answer is +1.4 as it is highlighted on the number line and -1.4 and +1.4 cancel out each other
Step-by-step explanation:
B.{-2,-4}
C.{12,14}
D.{-12,-14}
E.{0,5}
Answers
Answer:
Option A is correct
{2, 4} is, the function's domain.
Step-by-step explanation:
Domain is the set of all values of x for which function f(x) is defined.
Range is the set of all complete value of f.
Given the function:
The range of the function is {7, 9}
When f(x) = 7
then;
Subtract 5 from both sides we have;
x = 2
When f(x) = 9
then;
Subtract 5 from both sides we have;
x = 4
⇒Domain = {2, 4}
Therefore, the function's domain is, {2, 4}
f(x)= x+5
y=x+5
7=x+5
x=2
---------
y=x+5
9=x+5
x=4
Answers
To find the width of the rectangular parking lot, we can use the formula for the perimeter of a rectangle:
Perimeter = 2 * (Length + Width)
Given that the length of the parking lot is 92 meters and the perimeter is 298 meters, we can substitute these values into the formula:
298 = 2 * (92 + Width)
Let's solve this equation for the width:
298 = 2 * 92 + 2 * Width
298 = 184 + 2 * Width
298 - 184 = 2 * Width
114 = 2 * Width
Width = 114 / 2
Width = 57
Therefore, the width of the rectangular parking lot is 57 meters.