A large container holds 5 gallons of water. it begins leaking at a constant rate. After 10 minutes the container has 3 gallons of water left. at what rate is the water leaking?

Answers

Answer 1

Answer:

The required rate of water leaking is 0.2 gallons of water per minute.

Given that,

A large container holds 5 gallons of water. it begins leaking at a constant rate. After 10 minutes the container has 3 gallons of water left. at what rate is the water leaking is to be determined.

What is the rate of change?

The rate of change is defined as the change in value with the rest of the time is called rate of change.

Here,
Total volume = 5 gallons
Volume left after 10 min = 3 gallons
Rate = [total volume - volume left] / 10
rate = 5 - 3 / 10
Rate = 2 / 10
Rate = 0.2

Thus, the required rate of water leaking is 0.2 gallons of water per minute.

Learn more about the rate of change here: brainly.com/question/13103052

#SPJ2

Answer 2

Answer: First we have to find how much water leaked
5galllons-3 gallons=2 galllos of water leaked
Now we know $(2 galllons)/(10 minutes)$
Finally we can simplify it $(2 gallons)/(10 minutes)= (1 gallon)/(5 minutes)$ - its the answer

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Need help asap pls!!

Answers

Answer:

6&8

8&12

3&8

Step-by-step explanation:

a least common multiple is the smallest positive integer that is divisible by both numbers.

Answer:

1. 6 and 8
2. 8 and 12
3. 3 and 8

All of these numbers above that I have mentioned are the least common multiple (LCM) of 24.

Please mark me the brainliest.

Can you solve 2/3(x+13)=22

Answers

$\frac { 2 }{ 3 } \left( x+13 \right) =22\n \n \frac { 3 }{ 2 } \cdot \frac { 2 }{ 3 } \left( x+13 \right) =22\cdot \frac { 3 }{ 2 }$

$\n \n x+13=\frac { 66 }{ 2 } \n \n x+13=33\n \n x=33-13\n \n x=20$

$(2)/(3)(x+13)=22\n2(x+13)=66\n2x+26=66\n2x=40\nx=20$

What is the answer for : -2 ÷ 2491937 .

Answers

Well, once you divide those, your answer would end up to be -8.02588508e-7.
I hope I helped! =D

What percent of 80 is 20

Answers

25% is the answer
Hope this helps and

Solve the linear equation 2.25 – 11j – 7.75 1.5j = 0.5j – 1

Answers

we have

$2.25 - 11j - 7.75+ 1.5j = 0.5j - 1$

Solve for j

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$2.25 - 11j - 7.75+ 1.5j = 0.5j - 1\n 11j+0.5j-1.5j=2.25-7.75+1\n 10j=- 4.5\n\n j= -(4.5)/(10) \n \n j=-0.45$

therefore

the answer is

$j=-0.45$

First you will want all the j variables on one side, and you'll want to simplify it. Additionally, I like to change subtraction to addition of the opposite.

2.25 + (-11j) + (-7.75) + 1.5j = 0.5j + (-1)
-5.5 + (-9.5 j) = 0.5j + (-1)
-5.5 + (-9.5j) + (-0.5j) = -1
-5.5 + (-10j) = -1
-5.5 + 5.5 + (-10j) = -1 + 5.5
-10j = 4.5
-10j/-10 = 4.5/10
j = -0.45 assuming that 7.75 was added to 1.5 j

Emmanuel wants to tile his rectangular floor. he has two kinds of tiles to choose from, one of which is larger than the other. emmanuel hired your services to help him decide which tile to use.a.what area will be covered by 7"x7" tile? 21"x21" tilwe
b.if the rectangular floor has dimension of 420" by 630"
c.how many big square tiles are needed to cove rthe rectangular floor?
d.if each small tile costs P15.00 and each big tile costs P60.00which which tile should emmanuel use to econimize in tiling his floor? why?

Answers

a).
The 8" by 7" tile covers 49 square inches.
The 21" by 21" tile covers 441 square inches.

b).
The area of the floor is (420" x 630") = 264,600 square inches.

c).
It would take (264,600) / (441) = 600 large tiles to cover the floor.

d).
Emmanuel should use the big tiles to cover his floor.
-- A big tile costs 4 times as much as a small tile, but it has 9 times
as much area as a little tile has, so it is a better buy.
-- Plus, he would have to pay the floorman a lot more to glue down 5,400 tiles
than he will have to pay to glue down only 600 tiles.
-- Since he has hired my services to advise him, I will charge him only 15%
of the difference if he takes my advice, so he will still be money ahead.

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