Oy=2x+3
Oy = 3x + 6
F
Oy=-3x+23
Oy=-3x+6
22
The equation of a line parallel to line EF in slope-intercept form is Oy = 2x + b, where b is the y-intercept.
To determine the value of b, we will use the fact that this line passes through the point (2, 6).
Plugging in the x-coordinate of the point (2, 6) into the equation Oy = 2x + b, we get:
6 = 2(2) + b
6 = 4 + b
Subtracting 4 from both sides, we get:
2 = b
Therefore, the equation of the line parallel to line EF in slope-intercept form that passes through the point (2, 6) is:
Oy = 2x + 2.
Based on the amount that Benson could earn if he invested the additional interest for one year, the additional interest per month is $750.
This can be found by the formula:
= (Simple interest amount earned / Number of months in year) / Simple interest rate
Solving gives:
= (180 / 12) / 0.02
= 15 / 0.02
= $750
Find out more on additional interest at brainly.com/question/27037531.
#SPJ5
Answer:
Step-by-step explanation:
(x - 2)² + (y - 4)² = 25
(x - 2)² + (y - 4)² = 100
Answer:
Step-by-step explanation:
In the picture you can see that has endpoints of (-2, 1) and (6, 7)
x^2+10x+25=12
Answer: - 1.536 or - 8.464
Step-by-step explanation:
Step 1: Rearrange the equation, by putting everything on the left hand side of the equation so that the quadratic formula can be applicable to the equation
x^2-10*x+25-(12)=0
Step 2: the quadratic formula
- B ± √ B2-4AC
x = ————————
2A
Where A= 1
B = 10
C = 13
B2 - 4AC = 100 - 52
= 48
10 ± √ 48
x = —————
2
- √ 48
x =(10-√48)/2=5-2√ 3 = - 1.536
x =(10+√48)/2=5+2√ 3 = - 8.464
Are the two solutions