When the sum of an unknown number z and twenty-two is divided by the same unknown number, the quotient is twelve. What is the unknown number?

Answers

Answer 1

Answer: z+22/z = 12
z+22=12z
22=11z
2=z

Hope this helps. Just say if you need more of an explanation.

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Consider the following relation: {(1,12), (3,8), (3, 11), (6,9), (7,11)). Which orderedpair could be removed so that the relation is a function?

Answers

Answer:

(3,11) or (7,11)

Step-by-step explanation:

A function cannot have the same second number repeated ( forgot the term for the second number) so removing either (3,11) or (7,11) would leave it being a function

How is the process of finding equivalent ratios like the process of finding equivalent fractions

Answers

Finding equivalent ratios and finding equivalent fractions are basically the same thing. You need to divide the numerator and denominator

Procedure: define equilivant branch multiply the numerator and denominator by the same none 0

Plz help #s 13....14....15.....16....17......18

Answers

#14 is B, #16 is A, #17 is B #18 is C. I can't read #15 or #13. If you need to show work i will say in a differ comment.

Which values of m and b will create a system of equations with no solution? Select two options. y = mx + b y = –2x + A system of equations. y equals m x plus b. y equals negative 2 x plus StartFraction 3 over 2 EndFraction. A coordinate grid with a line labeled y equals negative 2 x plus StartFraction 3 over 2 EndFraction and passes through the points (9, 1.5) and (1, 0.5). m = –3 and b = m equals negative 3 and b equals negative StartFraction 2 over 3 EndFraction. m = –2 and b = m equals negative 3 and b equals negative StartFraction 1 over 3 EndFraction. m = 2 and b = m equals 2 and b equals negative StartFraction 2 over 3 EndFraction. m = m equals StartFraction 3 over 2 EndFraction and b equals negative StartFraction 2 over 3 EndFraction and b = m equals negative StartFraction 3 over 2 EndFraction and b equals negative StartFraction 2 over 3 EndFraction m = -2 and b = m equals negative 2 and b equals negative StartFraction 2 over 3 EndFraction

Answers

Answer:

B, E

Step-by-step explanation:

Given the first function:

$y=-2x+(2)/(3)$

A Linear System with no solutions is graphically represented by two parallel lines, therefore with the same slope. So in this case, m has to be equal to -2.

And to this inconsistent system, if the linear parameter is not so relevant. So if m=-2 then b may be either equal to -1/3 or -2/3 according to the options.

Given the alternatives

No Solution System:

$\left\{\begin{matrix}y=-2x+(2)/(3) & \n y=-2x-(1)/(3) & \end{matrix}\right.$

$\left\{\begin{matrix}y=-2x+(2)/(3) & \n y=-2x-(2)/(3) & \end{matrix}\right.$

Answer:

m = -2 and b = -1/3

m = -2 and b = -2/3.

Step-by-step explanation:

y = -2x - 1/3

y = -2x - 2/3

This system has no solutions because y cannot be 2 different values at once.

Mr. Scruggs got some money for his birthday. He spent 1/5 of it on dog treats. Then , he divided the he divided the remainder equally among his 3 favorite charities. What fraction of his money did each charity receive? If he donated $60 to each charity , how much money did he receive for his birthday

Answers

The remainder after dog treat is 4/5
On diving amongst 3 charities;
4/5÷3=4/15
4/15 is equivalent to 60
Then 15/15 will be equivalent 15*60/4
= 225 dollars

Answer: Fraction of money each charity received $=(4)/(15)$

He received $225 for his birthday.

Step-by-step explanation:

Let x denotes the money Mr. Scruggs received for his birthday.

Given : He spent 1/5 of it on dog treats.

i.e. Money he spent on dog treats = $(x)/(5)$

Remaining money = $x-(x)/(5)=(5x-x)/(5)=(4x)/(5)$

Since he divided the he divided the remainder equally among his 3 favorite charities.

⇒ Money each charity received = $(4)/(5)/ 3$

$=(4x)/(5)*(1)/(3)=(4x)/(15)$

∴ Fraction of money each charity received $=(4)/(15)$

If he donated $60 to each charity , then

$\Rightarrow\ (4x)/(15)=60\n\n\Rightarrow\ x=(60*15)/(4)=15*15=225$

∴ He received $225 for his birthday.

A drawer has some red ,green and blue marbles.there are 33 marbles . there are 4 times as many red marbles as green marbles.there are half as many blue marbles as green marbles.how many blue marbles are in the drawer?

Answers

Answer:

The number of blue marbles be 3.

Step-by-step explanation:

As given

A drawer has some red ,green and blue marbles.

There are 33 marbles .

there are 4 times as many red marbles as green marbles.

Let us assume that the number of green marbles be g .

Than Red marbles = 4g

There are half as many blue marbles as green marbles.

Than

$Number\ of\ blue\ marbles =\frac {Number\ of\ green\ marbles}{2}$

$Number\ of\ blue\ marbles =(g)/(2)$

Than the equation becomes

$g + 4g + (g)/(2) = 33$

Than simplify the above

$2g + 8g + g = 33* 2$

$11g = 66$

$g= (66)/(11)$

g = 6

$Number\ of\ blue\ marbles =(6)/(2)$

Number of blue marbles = 3

Therefore the number of blue marbles be 3 .

$g-green\ marbles\nr-red\ marbles\nb-blue\ marbles\ng+r+b=33\n\n4g-red\ marbles\n(1)/(2)g-blue\ marbles\n\ng+4g+(1)/(2)g=33\n\n5(1)/(2)g=33\n\n(11)/(2)g=33\ \ \ \ /\cdot(2)/(11)\n\ng=3\n\nAnswer:b=(1)/(2)g\to b=(1)/(2)\cdot6=3$

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