12 less than one-eleventh of some number, w"

Answers

Answer 1

Answer:

The required number is 132.

It is required to find the number.

What is arithmetic?

Arithmetic is the branch of mathematics that deals with the study of numbers using various operations on them. Basic operations of math are addition, subtraction, multiplication and division. These operations are denoted by the given symbols.

Given:

According to given question we have,

Let the number be x.

1/11w - 12

1/11w-12=0

Add 12 both sides we get,

1/11w-12+12=0+12

1/11w=12

w = 132

Therefore, the required number is 132.

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Answer 2

Answer:

Let w be the number.

1/11w - 12

1/11w-12=0

1/11w-12+12=0+12

1/11w=12

1/11w÷1/11=12÷1/11

w = 132

Therefore, the equation would be 1/11w - 12 and the value of w is 132.

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(2a^2 +a + 3) (a - 1)

Answers

Answer: 2a^3-a^2+2a-3

Step-by-step explanation:

(2a^2+a+3) (a-1)

2a^3-2a^2+a^2-a+3a-3

2a^3-a^2+2a-3

Note: If you need extra help with this topic, I suggest you should search up "how to multiply a trinomial by a binomial" on Google. It will help you a lot!

If f(x)=5x^3-2 and g(x)=2x+1, find (f+g)(x).

Answers

$(f+g)(x)=f(x)+g(x)\n\n(f+g)(x)=5x^3-2+2x+1\n(f+g)(x)=5x^3+2x-1$

Y=15x+500 what is the answer for y?

Answers

Subtract 500 from 500 then it would be y=15x. Then divide 15x from 15 and the answer would be y=x

The length of a rectangle is one more than five times its width. If a perimeter is 38, find the dimensions . Show work .

Answers

A rectangle's length is one greater than five times its breadth. if the perimeter is 38. This will have dimensions of 3 and 16.

What are the dimensions of a rectangle?

There are two dimensions to a rectangle: the length and the width, which are measured in relation to the length. Oval and triangular interiors have only two dimensions.

Since a rectangle is a two-dimensional form, it has two dimensions: length and width. The rectangle's length is its longer side, while its width is its shorter side.

Area only has two dimensions. length into width In some circumstances, we might state that dividing a length by a length produces the area of a square. The methods used to collect area vary depending on the shape.

A dimension, whether it be in terms of length, width, height, or something else, is a solid place to start when looking at a figure's other characteristics. The distance along the figure's outer edge is measured in terms of its perimeter.

Width = x

Length = 5x + 1

2x + 2(5x + 1) = 38

2x + 10x +2 = 38

12x = 38 - 2

x = 36 / 12

x=3

After this, value of x will be putted in 5x + 1.

Therefore, a rectangle's length is one greater than five times its breadth. if the perimeter is 38. This will have dimensions of 3 and 16.

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$x-width\n5x+1-length\n\n2x+2(5x+1)=38\n\n2x+10x+2=38\n\n2x+10x=38-2\n\n12x=36\ \ \ \ \ \ |:12\n\nx=3\n\n5\cdot3+1=15+1=16\n\nDimensions:\ 3\ and\ 16$

Ashley needs to ride her bike to her friends house 96 miles away. She is riding at an average rate of 15 miles per hour. She has 6 hours to get there. Will she make it?

Answers

The relationship between Speed, Distance and Time can be expressed as:

$\rm Distance = Speed * Time$

The total distance to be covered is 96 kilometres. Ashley couldn't cover it with existing speed and in available time.

Given:

$\rm{Average\; speed \;of\; Ashley} =(15\;mile)/(hour)$

$\rm{Time\; available} = 6\;hours$

Now, calculate the maximum distance that is possible to cover.

$\begin{aligned}\rm Distance &= \rm{Speed * Time}\n&=15 * 6\n&=90\end{aligned}$

The total distance to be covered by her is 96 kilometres. Ashley could cover only 90 kilometres.

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Average speed of Ashley = 15 miles per hour

Time she has = 6 hours

Distance can be covered = speed × time = 15×6 = 90 miles

But the distance of her friend's house is 96 miles.

So she will not be able to make it.

Evaluate 10 + 8 ÷ 2 − 4.

10
5
6
14

Answers

the rank of ( divide and multiply) is higher than ( summation and subtraction ) so we divide 8/2 first
10+(8/2)-4
10+4-4= 10

Hi Brainiac

10+8 ÷ 2-4

10+4-4

= 14-4

= 10

I hope that's help:)

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