What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?

Answers

Answer 1
Answer: 2×2 - 10x - 3= 0
=4 - 10x -3=0
=1-10x=0
=1=10x
⇒x=1/10

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Simplify each side of the following equation before applying the addition propertyx − 9 + 6 = −5 − 4

Answers

-9+6 = -3
-5 - 4= -9
so it's 
x-3=-9 OR
x=-6
X-9+6=-5-4
x-3=-9
x=-6

a number, half of that number, and one-third of that number are added. the result is 22. what is the number?

Answers

Let the number be x.

Half of that number  =  x / 2
One third of the number  =  x / 3

=  x / 2 + x / 3 = 22.  LCM  =  6.

= (3x + 2 x) / 6  = 22.

5x / 6 = 22.      Cross multiply

5x = 6 * 22.

5x = 132      Divide both sides by 5.

x =  132 / 5

x = 26.4

The number is 26.4.  Cheers.

By the congruent supplementary theorem, what can you conclude

Answers

Short Answer Only B is true.
Reasoning
A
A is not True. CBG is not equal to DBG. They are supplementary but not equal.


B is correct.

C
CBG = DBF are given as equal. It is not necessarily true that they are supplementary. That would be true only if they were both 90o

D
The two angles are equal, but they are not supplementary. They would be only if both were 90o which is shown not to be the case.


Answer:

The second option is what we can conclude.

Step-by-step explanation:

Angles FBC and DBG are congruent also because they are Opposite Angles by the Vertex, we can see trough vertex B, and neither angles have a common segment.

4a+b-3=2b
is this a linear equation?

Answers

4a+b-3=2b\n\n4a-3=2b-b\n\nb=4a-3\n\nthis\ is\ a\ linear\ eqation

The height , H , in feet of an object above the ground is given by h(t)=-16t^2+64t+190 , where t is the time in seconds . What is the height of the object after 2 seconds

Answers

After 2 seconds.
h(2) = -16(2)^2 + 64(2) + 190 = -16(4) + 128 + 190 = -64 + 128 + 190 = 254 feet

Final answer:

The height of the object after 2 seconds is 254 feet.

Explanation:

The height of an object after 2 seconds can be found by substituting t = 2 into the equation for height:

h(2) = -16(2)² + 64(2) + 190

h(2) = -64 + 128 + 190

h(2) = 254

Therefore, the height of the object after 2 seconds is 254 feet.

Learn more about height here:

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A student was investigating how many students in their class share a car ride to school.The table shows the results.
If 26 students travel by car, and some student travel together, answer the following.

(a) What is the missing frequency?
(b) What is the mean number of students in each car?


Number of students in one car Number of cars
1 n
2 7
3 3

Answers

If 26 students were riding, then the missing frequency for the number of cars for each student. Because:

2x7 = 14
+
3x3 =9 
=
23 students. Therefore there were 3 cars with only 1 student riding in each car. 

The mean number of students in each car is 2. Because:

mean for 3 cars = 1
mean for 7 cars = 2
mean for 3 cars = 3

Add it all up and divide by 3 means yields 2.