MATHEMATICS HIGH SCHOOL

How many times does 4 go into 48?

Answers

Answer 1
Answer:

Answer:

Number of times 4 is gone through to get 48 = 12

Step-by-step explanation:

The number which is formed after the product is given to be 48

Now, we need to find how many times 4 is gone through to get the final result as 48

4 × 1 = 4

4 × 2 = 8

4 × 3 = 12

4 × 4 = 16

4 × 5 = 20

4 × 6 = 24

4 × 7 = 28

4 × 8 = 32

4 × 9 = 36

4 × 10 = 40

4 × 11 = 44

4 × 12 = 48

Hence, Number of times 4 is gone through to get 48 = 12
Answer 2
Answer: 12, because 48 divided by 4 is 12

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X+y=0 and x-y=10 solve by substitution.. How do I figure out the problem!

Write a real world example, then solve.
5x + 4 = 2x +14

Answers

Answer:

x=10/3

Step-by-step explanation:

Answer: 10/3

Step-by-step explanation:

Let's solve your equation step-by-step.

Step 1: Subtract 2x from both sides.

Step 2: Subtract 4 from both sides.

Step 3: Divide both sides by 3.

Power set of {e,f,m,n,o}

Answers

\{\emptyset,\{e\},\{f\},\{m\},\{n\},\{o\},\{e,f\},\{e,m\},\{e,n\},\{e,o\},\{f,m\},\{f,n\},\n \{f,o\},\{m,n\},\{m,o\},\{n,o\},\{e,f,m\},\{e,f,n\},\{e,f,o\},\{e,m,n\},\n \{e,m,o\},\{e,n,o\},\{f,m,n\},\{f,m,o\},\{f,n,o\},\{m,n,o\},\{e,f,m,n\},\n \{e,f,m,o\},\{e,f,n,o\},\{e,m,n,o\},\{f,m,n,o\},\{e,f,m,n,o\}\}
n=5\ \ \ \Rightarrow\ \ \ 2^n=2^5=32\n\n

\emptyset;\n\{e\},\{f\},\{m\},\{n\},\{o\};\n\{e,f\},\{e,m\},\{e,n\},\{e,o\},\{f,m\},\{f,n\},\{f,o\},\{m,n\},\{m,o\},\{n,o\};\n\{e,f,m\},\{e,f,n\},\{e,f,o\},\{e,m,n\},\{e,m,o\},\{e,n,o\},\{f,m,n\},\n\{f,n,o\},\{f,m,o\},\{m,n,o\};\n\{e,f,m,n\},\{e,f,m,o\},\{e,f,n,o\},\{e,m,n,o\},\{f,m,n,o\};\n\{e,f,m,n,o\}

Maximum or Minimum. Domain and range of
y=x^2-4x+4

Answers

y=x^2-4x+4\n\na=1;\ b=-4;\ c=4\n\na > 0\ then\ minimum:\n\n(-b)/(2a)=(-(-4))/(2\cdot1)=(4)/(2)=2\n\ny_(min)=2^2-4\cdot2+4=4-8+4=0\n\n\ndomain:x\in\mathbb{R}\n\n\nrange:y\in\left<0;\ \infty\right)

A sports ball has a diameter of 16 cm. Find the volume of the ball.

Answers

Answer:

4/3 pi radius cubed

Step-by-step explanation:

4/3 pi x (8x8x8)

512 x 4/3 pi

2144.660585

Ohama is landing a plane on the runway. He's trying to decide where he should deploy the plane's landing gear so that the plane comes to a stop exactly at the end of the runway. The runway is 600 yards long, and the plane will travel half the distance with the landing gear than without the landing gear. Where should he deploy the landing gear ?

Answers

Answer:

Let's define:

A = distance traveled before deploying the landing gear

B = distance traveled after deploying the landing gear.

We must have that the sum of those two distances must be equal to 600 yards.

A + B = 600 yd.

And we know that:

" the plane will travel half the distance with the landing gear than without the landing gear."

Then we have that:

B = A/2.

Now we can replace this last equation in the first one:

A  + B = 600yd

A + A/2 = 600yd.

(3/2)*A = 600yd.

A = (2/3)*600yd = 400yd.

Ohama should deploy the landing gear 400 yd into the runway.

Solve for x: |x − 2| 10 = 12 a.) x = 0 and x = 4
b.) x = −4 and x = 0
c.) x = −20 and x = 4
d.) no solution

Answers

|x - 2| + 10 = 12
|x - 2| = 12 - 10 = 2
x - 2 = 2 or x - 2 = -2
x = 2 + 2 or x = -2 + 2
x = 4 or x = 0
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