What is the product or two squared and two to the sixth power?

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Answer 1
Answer: Use:a^n* a^m=a^(n+m)\n\n2^2*2^6=2^(2+6)=2^8\n\n2^8=2*2*2*2*2*2*2*2=256

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Round 35,894 to the nearest thousand.
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Is 6,500 ten times as much as 65 explanation and how to get the answer

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No, 6,500 is one hundred times as much as 65, because of the two zeros on the end.  100 and 6,500.

Is 5.4and 5.400 equal

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yes because the zeroes on 5.400 are just added as a filler they dont mean anything
they are equal no matter how many zeros you add at the end, its like 6.5 is equal to 6.5000000000 

Find the distance cd rounded to the nearest tenth. c=(8,-3) and D=(-9,-6)

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The distance CD rounded to the nearest tenth is approximately 17.3 units.

Here, we have to find the distance CD between points C(8, -3) and D(-9, -6), we can use the distance formula:

Distance CD = √[(x₂ - x₁)² + (y₂ - y₁)²]

where (x₁, y₁) are the coordinates of point C and (x₂, y₂) are the coordinates of point D.

Substitute the values:

Distance CD = √[(-9 - 8)² + (-6 - (-3))²]

Distance CD = √[(-17)² + (-3)²]

Distance CD = √[289 + 9]

Distance CD = √298

Now, round the result to the nearest tenth:

Distance CD ≈ 17.262

So, the distance CD rounded to the nearest tenth is approximately 17.3 units.

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  • Distance Formula: √((x_2-x_1)^2+(y_2-y_1)^2)

Plug the coordinates into the distance formula and solve as such:

CD=√((8-(-9))^2+(-3-(-6))^2)\nCD=√(17^2+3^2)\nCD=√(289+9)\nCD=√(298)\nCD\approx 17.3

Your answer is 17.3 units.

Help Marking Brainlest

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Answer:

g = 12.8

Step-by-step explanation:

g/4 = 3.2

Multiply both sides by 4

g/4 * 4 = 3.2 * 4

g = 12.8

Answer:  g = 12.8

answer: g=12.8 || g=3.2(4)

List the first five multiples of 1

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THE FIRST 5 MULTIPLES OF 1 ARE:1,2,3,4,AND 5
it should be 1,2,3,4,5

Recall that the length a spring  streches varies directly with the amount of weight attached to it. a certain spring stretches 5cm when a 10-gram weight is attached  write a direct variation equation relating the weight x and the amount of stretch y.

Answers

Direct variation is y=kx

In this case, y=1/2x. The spring stretches 5 cm for every 10 grams. Therefore if y=5 and x=10, k would have to be 1/2. That's how we come up with our direct variation model.




This\ spring\ stretches\ in\ proportion\ to\ weight,\ that\ is,\ for\ every \n 10\ grams\ of\ weight\ the\ amount\ of\ stretch\ is\ 5\ cm.\n \nx\ [g]\ \ \ |\ \ 10\ \ |\ \ 20\ \ |\ \ 30\ \ |\ \ 40\ \ |...|\ \ \ a\ \ \ |\n------------------\ny\ [cm]\ |\ \ 5\ \ \ |\ \ 10\ \ |\ \ 15\ \ |\ \ 20\ \ |...|\ \ (1)/(2) a\ \ |\n\na\ variation\ equation\ is\ y= (1)/(2) x