Please help me with this problem

Answers

Answer 1

Answer: I think the answer is A. Hope this help

Answer 2

Answer: A is the answer
So your welcome

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ILL GIVE YOU BRAINLIEST IF YOU GET IT RIGHT AND EXPLAIN A circular walkway surrounds a fountain.The fountain alone has a diameter of 16 feet.The walkway adds an additional 4 feet to each side. What is the area of the walkway minus the area of the fountain. Use 3.14 for Pi.

Answers

Answer:

Step-by-step explanation:

$A_(circle)=\pi r^2\n\nA=\pi r_(walkway)^2-\pi r_(fountain)^2\n\nA=\pi(20^2-16^2)=244\pi$

use a calculator fo find the value

Answer:

a = 452.16 ft² area of walkway

a = -351.68 ft² area of the walkway minus the area of the fountain

Step-by-step explanation:

Area fountain

a = π16²

a = 256π

Area fountain and walkway

a = π(16 + 4)²

a = π20²

a = 400π

Area Walkway

a =400π - 256π

a = 144π

a = 144 * 3.14

a = 452.16 ft²

------------------------------

I think the Area of the Walkway is what the question should be asking for, but it asked for

"the area of the walkway minus the area of the fountain"

a = 144π - 256π

a = -112π

a = -112 * 3.14

a = -351.68

A psychologist designed a new aptitude exam to measure logical and analytical thinking abilities. The time allowed for the exam is 60 minutes, and the exam is made up of 35 multiple choice questions. The psychologist expects that an examinee will spend an average of 1.66 minutes answering each question, with a standard deviation of 0.73 minutes. What proportion of examinees will complete the exam on time? Carry your intermediate computations to at least four decimal places. Report your result to at least three decimal places

Answers

Answer:

52.79% of examinees will complete the exam on time.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = (X - \mu)/(\sigma)$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

There are 35 questions. The psychologist expects that an examinee will spend an average of 1.66 minutes answering each question, with a standard deviation of 0.73 minutes. This means that the mean and the standard deviation for the time to complete the test is $\mu = 35*1.66 = 58.1, \sigma = 35*0.73 = 25.55$ .

What proportion of examinees will complete the exam on time?

The time allowed for the exam is 60 minutes. So this proportion is the pvalue of Z when $X = 60$ . So:

$Z = (X - \mu)/(\sigma)$

$Z = (60 - 58.1)/(25.55)$

$Z = 0.07$

$Z = 0.07$ has a pvalue of 0.5279.

This means that 52.79% of examinees will complete the exam on time.

What is the average rate of change for this function for the interval from x= 2
to x = 4?

Answers

Answer:

Step-by-step explanation:

hn hn

You want to create an 80% confidence interval for the average age of people who attend U of O football games. You take a sample of 100 attendees and find the average age to be 43.7 years old with a standard deviation of 7 years. Find the value of t* for this confidence interval. Do not round your answer. Write your answer in decimal form, not as a fraction or percent.

Answers

Answer:

80% confidence interval for the average age of people who attend U of O football games is [42.795 , 44.604].

Step-by-step explanation:

We are given that a sample of 100 attendees and find the average age to be 43.7 years old with a standard deviation of 7 years.

So, the pivotal quantity for 80% confidence interval for the population average start up cost is given by;

P.Q. = $(\bar X - \mu)/((s)/(√(n) ) )$ ~ $t_n_-_1$

where, $\mu$ = sample average age = 43.7 years old

$\sigma$ = sample standard deviation = 7 years

n = sample of attendees = 100

$\mu$ = population average age of people

So, 80% confidence interval for the average age of people, $\mu$ is ;

P(-1.2915 < $t_9_9$ < 1.2915) = 0.80

P(-1.2915 < $(\bar X - \mu)/((s)/(√(n) ) )$ < 1.2915) = 0.80

P( $-1.2915 * {(s)/(√(n) )$ < ${\bar X - \mu}$ < $1.2915 * {(s)/(√(n) )$ ) = 0.80

P( $\bar X -1.2915 * {(s)/(√(n) )$ < $\mu$ < $\bar X +1.2915 * {(s)/(√(n) )$ ) = 0.80

80% confidence interval for $\mu$ = [ $\bar X -1.2915 * {(s)/(√(n) )$ , $\bar X +1.2915 * {(s)/(√(n) )$ ]

= [ $43.7 -1.2915 * {(7)/(√(100) )$ , $43.7 +1.2915 * {(7)/(√(100) )$ ]

= [42.795 , 44.604]

Therefore, 80% confidence interval for the population average age of people who attend U of O football games is [42.795 , 44.604].

Which ordered pair represents the y-intercept of the graph of the equation y= -4x - 7

Answers

Answer:

(0,-7)

Step-by-step explanation:

Answer:

(0,-7)

Step-by-step explanation:

Just took the test

Good luck :)

2. Use the graph of y=-x2 - 2x + 3 to solvethe equation –X2 - 2x + 3-0. What are
the solutions?
A 4
B -1 and 4
C 1 and -3

Answers

Answer:

1 and -3

Step-by-step explanation:

The values of the graph is where the graph intersect at the line x

Which is 1 and -3

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