Tell whether the ratios form a proportion. 9/4, 2/3
Answers
Answer:
No ratios do not form a proportion.
Step-by-step explanation:
For example you take these fractions 9/4 and 2/?
9 - 2
4 - ?
Solve: 4×2÷9= about 0.9
0.9≠ 3
Related Questions
An astronaut drops a rock into a crater on the moon. The distance, d(t), in meters, the rock travels after t seconds can be modeled by d(t)=0.8t^2. What is the average speed, in meters per second, of the rock between 5 and 10 seconds after it was dropped?
I need help, I don't understand this question. what is f(-3) if f(x)=|2x+1|+5
At Video Shack, movie rentals cost $3.99 each. the cost of renting three movies and one video game is $0.11 less than the cost of renting five video games. how much does renting a video game cost?
The quotient is33 3/4. What is the divisor? How do you know
Answers
Principal: 19,200
term: 5 years
a) Interest compounded annually:
A = 19,200 (1 + 0.036)^5
A = 19,200 (1.036)^5
A = 19,200 (1.1934)
A = 22,913.28
b) Simple Interest
I = 19,200 * 0.038 * 5
I = 3,648.38
19,200 + 3,648.38 = 22,848.38
c) Interest compounded annually
A = 19,200 (1 + 0.034)^5
A = 19,200 (1.034)^5
A = 19,200 (1.182)
A = 22,694.40
d) Interest compounded quarterly
A = 19,200 (1 + 0.032/4)^4*5
A = 19,200 (1 + 0.008)^20
A = 19,200 (1.008)^20
A = 19,200 (1.173)
A = 22,521.60
(a) What does the difference between 50 and 55 mean in the real-world context?
(b) What does the difference between 200 and 150 mean in the real-world context?
Answers
judging from the question, I would assume that his fees are y=200+50x
I will assume that y=fee and x=number of hours (or units of time)
so
a. difference between 55 and 50, that is 5 so #2's fee is 5$ more for every hour he works
b. difference between200 and 150 means that contractor 1 gets 50 more initally than contractor 2
Answers
Answers
Diaz family spend $ 20 if they bought 3 adults tickets and 1 children's ticket
Solution:
Let "a" be the cost of each adult ticket
Let "c" be the cost of each student ticket
The Spencer family bought 3 adult tickets and 2 children's tickets for $23.50
Therefore, we frame a equation as:
3a + 2c = 23.50 --------- eqn 1
The Yang family bought 2 adult tickets and 4 children's tickets for $25
Therefore, we frame a equation as:
2a + 4c = 25 ----------- eqn 2
Let us solve eqn 1 and eqn 2
Multiply eqn 1 by 2
6a + 4c = 47 ---------- eqn 3
Subtract eqn 2 from eqn 3
6a + 4c = 47
2a + 4c = 25
( - ) --------------
4a = 47 - 25
4a = 22
Divide both sides of equation by 4
a = 5.5
Substitute a = 5.5 in eqn 1
3(5.5) + 2c = 23.50
16.5 + 2c = 23.50
2c = 23.50 - 16.5
2c = 7
Divide both sides of equation by 2
c = 3.5
Thus, cost of each adult ticket = $ 5.5
Cost of each student ticket = $ 3.5
How much would the Diaz family spend if they bought 3 adults tickets and 1 children's ticket?
Total cost = 3a + 1c
Total cost = 3(5.5) + 1(3.5) = 16.5 + 3.5
Total cost = 20
Thus Diaz family spend $ 20
Answers
Answers
Answer:
X=2 Y=-2 for 3x+y=4 X=2 Y=2 for x-3y=-4
Step-by-step explanation:
3x+(-2)=4
3x2+(-2)=4
6+(-2)=4
X-3y=-4
2-3x2=-4
2-6=-4
Hope this helped!