Find the absolute value. The absolute value of 5 is
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Answer:
5
Step-by-step explanation:
you need to look at how far it is from a m=number line to find the absolute value
Answer:
5
Step-by-step explanation:
The reason it is 5, not -5, is because the absolute value can never be a negative number! Only positive. Remember that
Cheers! Hope you understand
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the sum of Marys age and her moms age is 67. Three times Marys age increased by 7 is her moms age. How old is Mary and her mother
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The volume of a right circular cone is 22.11 in³.
What are algebraic expressions?
- In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.
- Mathematical symbols can designate numbers (constants), variables, operations, functions, brackets, punctuation, and grouping to help determine order of operations and other aspects of logical syntax.
Given is a right circular cone that has a height of 2.6 in and a base with a diameter of 5.7 in.
The volume of a right circular cone is -
V = {πr²h/3}
V = {π(d/2)²h/3}
V = {πd²h/12}
V = {3.14 x 5.7 x 5.7 x 2.6}/12
V = 22.11 in³
Therefore, the volume of a right circular cone is 22.11 in³.
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Answer:
22.12 cubic inch rounded to the nearest tenth is 22.1 cubic inch.
Step-by-step explanation:
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Hello,
All the numbers must begin with 6.
There are still 2,3,4,5 digits : 4 possibilities.
4!=4*3*2*1=24
The first is 62345 and the last 65432.
Final answer:
To find the number of odd numbers greater than 60000 that can be formed using the given numbers with each digit used only once, you can determine the number of possibilities for each digit and multiply them together. The answer is 96.
Explanation:
To find the number of odd numbers greater than 60000 that can be formed using the numbers 2, 3, 4, 5, and 6 with each digit used only once, we need to consider the possible arrangements of these digits. First, we can determine the number of possibilities for the leftmost digit, which must be either 3, 4, 5, or 6. Next, we can determine the number of possibilities for the remaining four digits, which can be arranged in 4! (4 factorial) ways. Multiplying these two values gives us the total number of odd numbers greater than 60000 that can be formed using these digits with each digit used only once.
Thus, the number of odd numbers greater than 60000 that can be formed using the numbers 2, 3, 4, 5, and 6 with each digit used only once is 4 * 4! = 4 * 4 * 3 * 2 * 1 = 96.
Learn more about Odds numbers greater than 60000 here:
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Let C the center of wheel.
P is the Carl's seat
A is the intercept of the horizontal line passing by A and the vertical line passing by P
In the right triangle PAC, sin 72°=AP/CP
==>
The height of Carl's seat is 11-8.5595...=2.440491...(m)
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Answer:
1/3
Step-by-step explanation:
In the coin there is heads or tails (2 possible results), so the probability of tossing heads is 1/2
For the number cube, we have 6 possible results. If we want a result greater than two, we have 3, 4, 5 or 6, so we have 4 of the 6 results, then the probability is 4/6.
Now, to find the final probability, we multiply both probabilities above:
Probability = (1/2) * (4/6) = 2/6 = 1/3
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We have to multiply numerator and denominator by: √(25-h)+ 5: