Substance X has a specific heat capacity that is twice as large as Substance Y. If both samples ended up at the same change in temperature from the same amount of energy added, what is the relationship between the masses of the two samples? Explain.
Answers
Answer:
Substance X has a smaller mass
Explanation:
The relationship between the mass of the two samples is that the mass of X is smaller compared to the mass of Y.
The specific heat capacity is given as:
C =
We can see that the higher the specific heat capacity the lesser the mass or simply put, the specific heat capacity of a body is inversely related to its mass.
If the amount of heat is constant i.e the same and the specific heat capacity of X is twice that of Y, then substance X has a smaller mass
Final answer:
The relationship between the masses of Substance X and Substance Y is mx : my = (cY) : (cX), which means that the ratio of their masses is equal to the inverse of the ratio of their specific heat capacities.
Explanation:
To determine the relationship between the masses of Substance X and Substance Y, we can use the equation Q = mcΔT, where Q represents the amount of heat added, m represents the mass of the substance, c represents the specific heat capacity, and ΔT represents the change in temperature.
Let's assume that the same amount of energy is added to both Substance X and Substance Y, resulting in the same change in temperature. Since Substance X has a specific heat capacity that is twice as large as Substance Y, we can set up the following equation:
mx(cX)ΔT = my(cY)ΔT
Canceling out ΔT on both sides of the equation, we get:
mx(cX) = my(cY)
To find the relationship between the masses, we can divide both sides of the equation by (cY) and simplify:
mx / my = (cY) / (cX)
Therefore, the relationship between the masses of Substance X and Substance Y is mx : my = (cY) : (cX), which means that the ratio of their masses is equal to the inverse of the ratio of their specific heat capacities.
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Answer: The correct option is 3.
Explanation: Radioisotopes which emits alpha-particle are known as alpha-emitters. These radioisotopesundergo alpha-decay.
The radioisotopes which emits beta-particle are known as beta-emitters. These radioisotopes undergo beta-minus decay. In this decay a neutron gets converted to a proton and an electron.
The radioisotopes which emits positron-particle are known as positron-emitters. These radioisotopes undergo beta-plus decay. In this type of decay a proton gets converted to a neutron.
From the given options,
Option 1: All the three radioisotopes undergoes beta-minus decay.
Option 2: Cs-137 and Tc-99 radioisotopes undergo beta-minus decay.
Fr-220 is a radioisotope which undergoes alpha-decay.
Option 3: Radioisotope Kr-85 undergoes beta-minus decay.
Radioisotope Ne-19 undergoes positron decay.
Radioisotope Rn-222 undergoes alpha decay.
Option 4: All the three radioisotopes undergoes beta-minus decay processes.
Hence, from the above information, the correct option is 3.
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Final answer:
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Explanation:
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Answers
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Answer:
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