MATHEMATICS HIGH SCHOOL

*Which does NOT describe SLOPE?

unit rate
rate of change
"per"
initial value

Answers

Answer 1
Answer:

Unit Rate is the correct answer, I know because it is the correct answer

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What are the first five terms in the arithmetic sequence An=6n, starting with n=1?

Answers

The arithmetic sequence : A n = 6 n
A 1 = 6 * 1 = 6
A 2 = 6 * 2 = 12
A 3 = 6 * 3 = 18
A 4 = 6 * 4 = 24
A 5 = 6 * 5 = 30
Answer:
The first five terms in the sequence are:  6, 12, 18, 24 and 30. 

It costs $4.25 for one pound of roast beef and $3.70 for one pound of ham. How much will it cost to purchase 2 pounds of roast beef and 3.5 pounds of ham?

Answers

11.45$ because u have to add the numbers up together

How long will it take a sample of radioactive substance to decay to half of its original amount, if it decays according to function A(t)=750e^ -.119t, where t is the time in years? Round your answer to the nearest hundredth year. T equals time???? I don't see the time anywhere! Can someone please help me figure this mess out?

Answers

This is the formula to find the amt. A of that radioactive substance after time t.

A_t=750e^(0.119t)

We want to find out low long it will take for A to become half of its original amount.
We don't know the original amount, and the substance is not decaying at a constant rate (but rather an exponential one) so we can't answer that question.

Is there any information you forgot to give? Double check yourself.

Can you solve 9 5/9 + 1 1/5

Answers

9 5/9 + 1 1/5

9 + 1 = 10

5/9 + 1/5 = 25/45 + 9/45 = 34/45

10  34/35 is the answer
8   5 /9   +  1  1/5

8 + 1 = 9.        5/9 + 1/5  = (5/9)*(5/5) + (1/5)*(9/9) = 25/45 + 9/45

= (25 + 9) /45 = 34/45

=  9      34/45

How do you do...
cos2x-sin2x=1-2sin2x

Answers

sin (2 \alpha) =2\cdot sin \alpha \cdot cos \alpha \ncos(2 \alpha )=1-2sin^2 \alpha \n-------------------- \ncos2x-sin2x=1-2sin2x\ncos2x+sin2x=1\n1-2sin^2x+2sinx\cdot cosx=1\n-2sinx(sin x-cosx)=0\n -2sinx=0\ \ \ \ or\ \ \ \ sinx-cosx=0\n\n1)\ -2sinx=0\ \ \Leftrightarrow\ \ sinx=0\ \ \Leftrightarrow\ \ x_1=k \pi \ \ and\ \ k\in I\n2)\ \ sinx-cosx=0\ \ \Leftrightarrow\ \ sinx=cosx\ /:cosx\ \ \ \ \ \wedge\ \ \ \ cos x \neq 0\ntanx=1\ \ \Leftrightarrow\ \ x_2= ( \pi )/(4) +k \pi \ \ and\ \ k\in I

(xa-b)/x=y
Make x the subject of the formula.

Answers

(xa-b)/x=y

xy=xa-b

xa-xy=b

x(a-y)=b

x=b/(a-y)
\frac{xa-b}x=y\nxa-b=xy\nxa-xy=b\nx(a-y)=b\nx=(b)/(a-y)
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