An object weighs 1 pound on earth weighs about 1/15 pounds on Pluto. If a man weighs 240 pounds on earth how many pounds would he weigh on Pluto?

Answers

Answer 1
Answer:

Answer:

16 I believe. 240 divided by 15 is 16.


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Find the seventh term of thegeometric sequence, given the
first term and common ratio.
a_=1 and r=-2/3
[?]

Answers

Answer:

T_7 = (64)/(729)

Step-by-step explanation:

Given

a =1

r = (2)/(3)

Required

Determine the 7th term

The nth term of a gp is:

T_n = a * r^{n-1

So, we have:

T_7 = 1 * (2)/(3)^{7-1

T_7 = 1 * (2)/(3)^{6

T_7 = 1 * (2^6)/(3^6)

T_7 = 1 * (64)/(729)

T_7 = (64)/(729)

Can someone please help me :)

Answers

Answer:

90 degree

Step-by-step explanation:

Three points A, B, and C are added and shown in attached picture.

As the property of inscribed angle in circle:

angle BAC = (1/2) x 88 = 44 deg

As the property of complement angle:

angle ABC = 180 - 89 = 91 deg

As the property of sum of three angles in a triangle:

angle ACB + angle ABC + angle BAC = 180 deg

=> angle ACB = 180 - angle ABC - angle BAC = 180 - 44 - 91 = 45 deg

One more time, we use the property of inscribed angle in circle:

x = 2 x angle ACB = 2 x 45 = 90 deg

Hope this helps!

An athlete eats 85 grams of protein per day while training. How much is this in milligrams ?

Answers

Answer: 85,000 milligrams

1 gram= 1,000 milligrams

85 × 1,000 = 85,000 milligrams

From 1985 to 2007, the number B B of federally insured banks could be approximated by B ( t ) = − 329.4 t + 13747 B(t)=-329.4t+13747 where t is the year and t=0 corresponds to 1985. How many federally insured banks were there in 1990?

Answers

The number of federally insured banks in the year 1990 was 12,100.

Given data:

To find the number of federally insured banks in the year 1990, you need to substitute the value of t = 1990 into the given function B(t):

B(t) = -329.4t + 13747

Since t corresponds to the year and t = 0 corresponds to 1985, we need to calculate for t = 1990 - 1985.

t = 5.

Substitute t = 5 into the function:

B(5) = -329.4 * 5 + 13747

Now, perform the calculations:

B(5) = -1647 + 13747

B(5) = 12100

Hence, there were approximately 12,100 federally insured banks in the year 1990.

To learn more about linear equations, refer:

brainly.com/question/10185505

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Final answer:

Using the given equation and by substituting t with 5 (for the year 1990, five years after 1985) in that equation, we find that there were 13363 federally insured banks in 1990.

Explanation:

The question is asking how many federally insured banks there were in 1990, given that the number of banks in any given year from 1985 to 2007 is given by the equation

B(t) = -329.4t + 13747

. In this equation,

t

is the year with t=0 corresponding to 1985. To find the answer, we should substitute in the appropriate value of t, which would be 5 because 1990 is five years after 1985. Thus, the equation becomes B(5) = -329.4*5 + 13747. This simplifies to 15010 - 1647, which equals

13363

. Therefore, there were 13363 federally insured banks in 1990.

Learn more about Mathematical modeling here:

brainly.com/question/30517381

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Joe work 21 hours on his class project. He worked 3 times as long is Marie did. How long did Marie work on a project? Translate and solve the equation

Answers

the answer is 21 ÷ 3 = 7 hrs
divide 21 by 3 and you will get 7

m=21/3

Y-3=2(x+1) please please help

Answers

Answer:

y=2x+5

Step-by-step explanation:

distribute 2 to x and 1, do this by multiplying each.

you should get y-3=2x+2.

then you have to move the -3 from the left to the right. but when you do this you have to change the -3 to a positive 3. then combine 3 and 2.

you then get the answer, y=2x+5.