Which ordered pair is the vertex of y=lx+5l

Answers

Answer 1

Answer: -5,0 is the correct answer .

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A line passes through the points (1, -6) and (4,3). What is the y-intercept of this line?○ -9
○ -3
○ 3
○ 9

Answers

After plugging in the points into the formula y2-y1/x2-x1, you’ll find that the slope is 3 or 3/1. Slope is written as rise over run. Using this information, you’ll see that the y-intercept is (0,-9). Hopefully I’m right and hopefully this helps!

Answer: -9

(-3/5, 7/5) and (2/5, 6/5) A. The equation of the line in slope-intercept form is ?
B. Standard Form
Please help

Answers

First, let's find the slope of the line using the formula $(y_2 - y_1)/(x_2 - x_1)$ , where $(x_1, y_1)$ and $(x_2, y_2)$ are points on the line.

The equation for the slope of this line would be:

$((7)/(5) - (6)/(5))/(-(3)/(5) - (2)/(5)) = ((1)/(5))/(-1) = -(1)/(5)$

Now, let's find use the point-slope equation to find an equation for our line, which is $(y - y_1) = m(x - x_1)$ , where $(x_1, y_1)$ is a point on the line and $m$ is the slope. The point-slope equation for our line would be:

$(y - (6)/(5)) = -(1)/(5)(x - (2)/(5))$

$y - (6)/(5) = -(1)/(5)x + (2)/(25)$

$y = -(1)/(5)x + (32)/(25)$

The slope-intercept form of the line would be y = -x/5 + 32/25.

Now, we can use operations to convert this equation into standard form:

$25y = -5x + 32$

$5x + 25y = 32$

The standard form of the line would be 5x + 25y = 32.

Divya wants to rent a car to drive for the weekend. The rental company has a special that allows her to rent it for $200 for the weekend, plus $0.07 per mile. Divya only has $230. Write an inequality, solve, and determine her limitations when renting.

Answers

Answer:

$200 + 0.07m \leq 230$

A maximum of $\approx$ 428 miles is the distance what Divya can travel.

Step-by-step explanation:

Given that:

Rent to be paid for the car in the weekend = $200

Charges to be paid per mile = $0.07

Total money available with Divya = $230

To find:

The inequality as per her limitations and solution to the problem.

Solution:

Let the number of miles for which Divya can drive = $m$ miles

Charges for one mile = $0.07

Charges for $m$ miles = $0.07 $m$

Total charges for renting and $m$ miles = Rental charges + Operational charges

Total charges for renting and $m$ miles = $200 + $0.07 $m$

These are charges must be lesser than equal to the amount of money available with Divya.

Therefore, we can write:

$200 + 0.07m \leq 230$

Subtracting 200 from both the sides:

$0.07m \leq 30$

Dividing both sides with 0.07:

$m \leq (30)/(0.07)\nm\leq 428.6$

Therefore, a maximum of $\approx$ 428 miles is the distance what Divya can travel.

I answered 5 questions that are EASY AS FUDGE LOL and i just want someones feedback to see if it is right WILL GIVE BRAINLIEST HELPPPPPPPPPPPPP at least take a look at it!1. The number of people that belong to a certain social website is 412 and growing at a rate of 5% every month.

How many members will there be in 9 months?

Enter your answer, rounded to the nearest whole number, in the box.

MY ANSWER IS: 639......RIGHT OR WRONG

2. The expression 15.85(1+x) gives the total cost of a toy, where x is the sales tax written in decimal form.

What does 1 + x represent in the expression?

percent of original price being paid in tax

cost of toy

percent of tax

amount of tax

3. A population of lizards decreases exponentially at a rate of 12.5% per year.

What is the equivalent monthly rate to the nearest hundredth of a percent?

0.20%

1.04%
1.11%

1.23%

4. Enrollment was increasing at a rate of 20% per year.

What was the monthly growth rate?

Enter your answer, rounded to the nearest tenth of a percent, in the box.

MY ANSWER IS: 1.7%

5. The value of a truck after t years is represented by the function f(t)=22,200(0.92)t .

What does the value 22,200 represent in this situation?

The value of the truck increases by $22,200 each year.

The initial value of the truck is $22,200.
The value of the truck decreases by $22,200 each year.

The value of the truck after t years is $22,200.

Answers

Answer:

1. The population increases exponentially, therefore the number of members in the team will increase by the equation modeled by :

$\text{Number of members = }a_0(1+(Rate)/(100))^(Time)\n\n\implies\text{Number of members = }412(1+(5)/(100))^9\n\n\implioes\text{Number of members after 9 months = }639$

2. Total cost of the toy is calculated by multiplying the initial cost and the amount of tax charged on the toy.

Here, 15.85 represents the initial cost of the toy

Hence, 1 + x represents the amount of tax charged on the toy.

3. Rate per year is given to be 12.5%

Now, to find monthly rate, divide the yearly rate by 12

$\text{Monthly Rate = }(12.5)/(12)=1.04\%$

4. Rate per year is given to be 20%

Now, to find monthly rate, divide the yearly rate by 12

$\text{Monthly Rate = }(20)/(12)\approx 1.7\%$

5. The value of a truck after t years is represented by the function f(t)=22,200(0.92)t .

Here, 2200 is the initial value of the truck.

Answer:

i got 185.4 so basically 184.

412 times 5% equals 20.6

times that by 9 for 9 months then that gives you the answer.

Plz help with questions number 1 and 2

Answers

Answer:

question 1=12

question 2= $3|-2x^2-4|-4$

Step-by-step explanation:

question 1

$u(t)=7t-2\n\ns(t)=t^(2)-9 \n\ns(u(2))=?\n\nu(2)=7(2)-2=14-2=12\n\nu(2)=12\n\ns(12)=(12)^2-9=144-9=135\n\ns(u(2))=135$

question 2

$f(x)=3|x+1|-4\n\ng(x)=-2x^2-5\n\nf(g(x))=?\n\ng(x)=-2x^2-5\n\nf(-2x^2-5)=3|(-2x^2-5)+1|-4\n\nf(g(x))=3|-2x^2-5+1|-4\n\nf(g(x))=3|-2x^2-4|-4\n\n$

Sal wants to save a minimum of $1200 over the summer by saving $125/wk. He has saved $230 so far.About how many weeks will it take Sal to save enough money?

A.
at least 12 wk

B.
at most 12 wk

C.
at least 8 wk

D.
at most 8 wk

Answers

If you would like to know the number of weeks to save enough money, you can calculate this using the following steps:

$1200 - $230 = $970

$970 / $125 = 7.76 weeks = 8 weeks

The correct result would be C. at least 8 weeks.

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