What is the slope-intercept form of the linear equation 2x–8y=322x–8y=32 ?
Answers
Answer 1
Answer:
2x - 8y = 32
-8y = -2x + 32
y = (-2/-8)x - 32/8
y = 1/4x - 4 <== slope intercept form
-8y = -2x + 32
y = (-2/-8)x - 32/8
y = 1/4x - 4 <== slope intercept form
Related Questions
Estimate the average annual growth rate of the world population for 1950, 1988, and 2010 using model 17 from the previous page.Model 17. Year Population Growth Rate (%)1972 1.961982 1.731992 1.52002 1.22
What is the volume of the right prism? A.3780 in3 B.16,800 in3 C.8400 in3 D.3360 in3
(–45t + 53s) and (–3 – 75s + 2t) add these
1) what is the meaning of commutative property?2)what is the meaning of distributive property?3)what is the meaning of associative property?
The Polleys want to put in a swimming pool next summer. They need to save $6,000 over 12 months in order to achieve this goal. They set aside the same amount each month and after 7 months discovered they have saved $3,100. The Polleys know that they must adjust their plan in order to meet their goal, so they come up with the following options:Option A: Save the original amount each month but put the pool in one month later than originally planned. Option B: Increase savings each month by $100 from their original plan
What is the volume of the right prism? A.3780 in3 B.16,800 in3 C.8400 in3 D.3360 in3
(–45t + 53s) and (–3 – 75s + 2t) add these
1) what is the meaning of commutative property?2)what is the meaning of distributive property?3)what is the meaning of associative property?
The Polleys want to put in a swimming pool next summer. They need to save $6,000 over 12 months in order to achieve this goal. They set aside the same amount each month and after 7 months discovered they have saved $3,100. The Polleys know that they must adjust their plan in order to meet their goal, so they come up with the following options:Option A: Save the original amount each month but put the pool in one month later than originally planned. Option B: Increase savings each month by $100 from their original plan
b. horizontal bar graph.
c. line graph.
d. moving bar chart.
Answers
A.) vertical bar graph
3x + y = 17
4x + y = 18
find for x and y
Answers
1st multiply the top equation by -1 to get -3x - y = -17 then add the 2 equations together to get:
4x + y - 3x - y = 18 - 17
x = 1 (simplified down)
Now plug the 1 into either equation
4(1) + y = 18
4 + y = 18
y = 18 - 4 = 14
Your point is (1, 14)
4x + y - 3x - y = 18 - 17
x = 1 (simplified down)
Now plug the 1 into either equation
4(1) + y = 18
4 + y = 18
y = 18 - 4 = 14
Your point is (1, 14)
Answers
You can do this !
The rectangular prism has
-- length = 10 cm
-- width = 7 cm
-- height = 3 cm.
-- The area of the top and bottom is (length x width) each.
-- The area of the left and right sides is (length x height) each.
-- The area of the front and back is (width x height) each.
There. I just laid out all the schmartz you need to answer this question.
The rest is all simple arithmetic, and you're perfectly capable of turning
the crank and getting the answer. You don't need anybody else to do
that part for you.
Don't forget your units. The area of each flat face is (cm) times (cm),
and that product will be some cm² , for area.
The rectangular prism has
-- length = 10 cm
-- width = 7 cm
-- height = 3 cm.
-- The area of the top and bottom is (length x width) each.
-- The area of the left and right sides is (length x height) each.
-- The area of the front and back is (width x height) each.
There. I just laid out all the schmartz you need to answer this question.
The rest is all simple arithmetic, and you're perfectly capable of turning
the crank and getting the answer. You don't need anybody else to do
that part for you.
Don't forget your units. The area of each flat face is (cm) times (cm),
and that product will be some cm² , for area.
Answers
11.
Lateral area of a cube is 4*[(2.5)^2] = 4*6.25 = 25 cm^2; B
Lateral area of a cube is 4*[(2.5)^2] = 4*6.25 = 25 cm^2; B
Answers
h(t) = -5t² + 20t + 1
-5t² + 20t + 1 = 0
t = -(20) +/- √((20)² - 4(-5)(1))
2(-5)
t = -20 +/- √(400 + 20)
-10
t = -20 +/- √(420)
-10
t = -20 +/- 2√(105)
-10
t = -20 + 2√(105) t = -20 - 2√(105)
-10 -10
t = 2 - 0.2√(105) t = 2 + 0.2√(105)
h(t) = -5t² + 20t + 1
h(2 - 0.2√(105)) = -5(2 - 0.2√(105))² + 20(2 - 0.2√(105)) + 1
h(2 - 0.2√(105)) = -5(2 - 0.2√(105))(2 - 0.2√(105)) + 20(2) - 20(0.2√(105)) + 1
h(2 - 0.2√(105)) = -5(4 - 0.4√(105) - 0.4√(105) + 0.04√(11025)) + 40 - 4√(105) + 1
h(2 - 0.2√(105)) = -5(4 - 0.8√(105) + 0.04(105)) + 40 + 1 - 4√(105)
h(2 - 0.2√(105)) = -5(4 - 0.8√(105) + 4.2) + 41 - 4√(105)
h(2 - 0.2√(105)) = -5(4 + 4.2 - 0.8√(105)) + 41 - 4√(105)
h(2 - 0.2√(105)) = -5(8.2 - 0.8√(105)) + 41 - 4√(105)
h(2 - 0.2√(105)) = -5(8.2) - 5(-0.8√(105)) + 41 - 4√(105)
h(2 - 0.2√(105)) = -41 + 4√(105) + 41 - 4√(105)
h(2 - 0.2√(105)) = -41 + 41 + 4√(105) - 4√(105)
h(2 - 0.2√(105)) = 0 + 0
h(2 - 0.2√(105)) = 0
(t, h(t)) = (2 - 0.2√(105), 0)
or
h(t) = -5t² + 20t + 1
h(2 + 0.2√(105)) = -5(2 + 0.2√(105))² + 20(2 + 0.2√(105)) + 1
h(2 + 0.2√(105)) = -5(2 + 0.2√(105))(2 + 0.2√(105)) + 20(2) + 20(0.2√(105)) + 1
h(2 + 0.2√(105)) = -5(4 + 0.4√(105) + 0.4√(105) + 0.04√(11025)) + 40 + 4√(105) + 1
h(2 + 0.2√(105)) = -5(4 + 0.8√(105) + 0.04(105)) + 40 + 4√(105) + 1
h(2 + 0.2√(105)) = -5(4 + 0.8√(105) + 4.2) + 40 + 1 + 4√(105)
h(2 + 0.2√(105)) = -5(4 + 4.2 + 0.8√(105)) + 41 + 4√(105)
h(2 + 0.2√(105)) = -5(8.2 + 0.8√(105)) + 41 + 4√(105)
h(2 + 0.2√(105)) = -5(8.2) - 5(0.8√(105)) + 41 + 4√(105)
h(2 + 0.2√(105)) = -41 - 4√(105) + 41 + 4√(105)
h(2 + 0.2√(105)) = -41 + 41 - 4√(105) + 4√(105)
h(2 + 0.2√(105)) = 0 + 0
h(2 + 0.2√(105)) = 0
(t, h(t)) = (2 + 0.2√(105), 0)
-5t² + 20t + 1 = 0
t = -(20) +/- √((20)² - 4(-5)(1))
2(-5)
t = -20 +/- √(400 + 20)
-10
t = -20 +/- √(420)
-10
t = -20 +/- 2√(105)
-10
t = -20 + 2√(105) t = -20 - 2√(105)
-10 -10
t = 2 - 0.2√(105) t = 2 + 0.2√(105)
h(t) = -5t² + 20t + 1
h(2 - 0.2√(105)) = -5(2 - 0.2√(105))² + 20(2 - 0.2√(105)) + 1
h(2 - 0.2√(105)) = -5(2 - 0.2√(105))(2 - 0.2√(105)) + 20(2) - 20(0.2√(105)) + 1
h(2 - 0.2√(105)) = -5(4 - 0.4√(105) - 0.4√(105) + 0.04√(11025)) + 40 - 4√(105) + 1
h(2 - 0.2√(105)) = -5(4 - 0.8√(105) + 0.04(105)) + 40 + 1 - 4√(105)
h(2 - 0.2√(105)) = -5(4 - 0.8√(105) + 4.2) + 41 - 4√(105)
h(2 - 0.2√(105)) = -5(4 + 4.2 - 0.8√(105)) + 41 - 4√(105)
h(2 - 0.2√(105)) = -5(8.2 - 0.8√(105)) + 41 - 4√(105)
h(2 - 0.2√(105)) = -5(8.2) - 5(-0.8√(105)) + 41 - 4√(105)
h(2 - 0.2√(105)) = -41 + 4√(105) + 41 - 4√(105)
h(2 - 0.2√(105)) = -41 + 41 + 4√(105) - 4√(105)
h(2 - 0.2√(105)) = 0 + 0
h(2 - 0.2√(105)) = 0
(t, h(t)) = (2 - 0.2√(105), 0)
or
h(t) = -5t² + 20t + 1
h(2 + 0.2√(105)) = -5(2 + 0.2√(105))² + 20(2 + 0.2√(105)) + 1
h(2 + 0.2√(105)) = -5(2 + 0.2√(105))(2 + 0.2√(105)) + 20(2) + 20(0.2√(105)) + 1
h(2 + 0.2√(105)) = -5(4 + 0.4√(105) + 0.4√(105) + 0.04√(11025)) + 40 + 4√(105) + 1
h(2 + 0.2√(105)) = -5(4 + 0.8√(105) + 0.04(105)) + 40 + 4√(105) + 1
h(2 + 0.2√(105)) = -5(4 + 0.8√(105) + 4.2) + 40 + 1 + 4√(105)
h(2 + 0.2√(105)) = -5(4 + 4.2 + 0.8√(105)) + 41 + 4√(105)
h(2 + 0.2√(105)) = -5(8.2 + 0.8√(105)) + 41 + 4√(105)
h(2 + 0.2√(105)) = -5(8.2) - 5(0.8√(105)) + 41 + 4√(105)
h(2 + 0.2√(105)) = -41 - 4√(105) + 41 + 4√(105)
h(2 + 0.2√(105)) = -41 + 41 - 4√(105) + 4√(105)
h(2 + 0.2√(105)) = 0 + 0
h(2 + 0.2√(105)) = 0
(t, h(t)) = (2 + 0.2√(105), 0)
9.4 × 1014
5.2 × 1042
6.12 × 1042
Answers
Answer:
Step-by-step explanation:
we know that
In this problem we have
therefore
remember
(x^m)(x^n)=x^(m+n)
and commutaitve property
(3.4 times 10^-14) times (1.8 times 10^28)=
(3.4)(10^-14)(1.8)(10^28)=
(3.4)(1.8)(10^-14)(10^28)=
(6.12)(10^(-14+28))=
(6.12)(10^14)
answer is first option
(x^m)(x^n)=x^(m+n)
and commutaitve property
(3.4 times 10^-14) times (1.8 times 10^28)=
(3.4)(10^-14)(1.8)(10^28)=
(3.4)(1.8)(10^-14)(10^28)=
(6.12)(10^(-14+28))=
(6.12)(10^14)
answer is first option