Simplify the equation -9b+2b-4+2

The particle passes through the origin at t = 0 and t = ±√20. The particle is instantaneously motionless at t = 0 and t = ±√10.

(a) To determine the times at which the particle passes through the origin, we need to find when the position function equals zero. So, we set s(t) = 0 and solve for t.
t4 - 20t2 = 0
Factoring out a t2, we get:
t2(t2 - 20) = 0
Setting each factor equal to zero and solving for t gives us the following solutions:
t = 0 (giving us the initial position), and t = ±√20 (approximately t = ±4.47).

(b) To determine when the particle is instantaneously motionless, we need to find when the velocity of the particle is equal to zero. The velocity function of the particle is the derivative of the position function. So, we differentiate s(t) with respect to t to find the velocity function.
v(t) = s'(t) = 4t³ -40t
Setting v(t) = 0, we have:
4t³ -40t = 0
Factoring out a 4t, we get:
4t(t² - 10) = 0
Setting each factor equal to zero and solving for t gives us the following solutions:
t = 0 (giving us the initial velocity), and t = ±√10 (approximately t = ±3.16).

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Final answer:

The particle passes through the origin at t = 0 and t = √20 seconds. The particle is instantaneously motionless at t = 0 and t = ±√10 seconds.

Explanation:

The position of the particle at time t is given by the equation s(t) = t4 - 20t2. To determine the times when the particle passes through the origin, we set s(t) equal to zero and solve for t. This gives us the quadratic equation t4 - 20t2 = 0, which can be factored as t2(t2 - 20) = 0. The solutions to this equation are t = 0 and t = ±√20. Since t cannot be negative in this scenario, the particle passes through the origin at t = 0 and t = √20 seconds.

To determine the times when the particle is instantaneously motionless, we need to find the times when the velocity of the particle is equal to zero. The velocity of the particle can be found by taking the derivative of the position function with respect to time, v(t) = 4t3 - 40t. Setting this equation equal to zero and solving for t gives us the cubic equation 4t3 - 40t = 0. This equation can be factored as 4t(t2 - 10) = 0. The solutions to this equation are t = 0 and t = ±√10. Therefore, the particle is instantaneously motionless at t = 0 and t = ±√10 seconds.

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Answer:

the answer is C -1-2 to the equation

Answer:

20

Step-by-step explanation:

mean is average

add all numbers get 160

divide by number of numbers (8) and get 20

Answer:

when you find the mean of a data set, you add all the numbers up then you divide the sum by the numbers in total. the sum is 160, you then divide by total of number which is 8 . your answer is 20. not sure if that made sense lol

Answer: $31 & It would be 6 trips!

Step-by-step explanation: 6 trips x $3 for the trips, is $18 plus the $13 to get in the park, would be equivalent to $31

Answer:

if she rides the slides 6 times, the costs will be the same: $31

Step-by-step explanation:

You can write an equation in order to solve this problem. Since you are trying to find how many trips using the (3t + 13) plan are equal to the plan that costs 31, the equation would be:

31 = 3t + 13

= 18 = 3t

= 6 = t

(3t + 13 stands for $3 a trip plus $13 entry fee)

This means that if Carla takes 6 trips using either plan, they will cost the same; both would cost $31.

if we were to use the quadratic formula, we would get that the roots are

or that the 2 seperate roots are

and

if we sum these, then the bits will cancel and we wil be left with

or or

the sum of the solutions is

Try this option:

According to the properties of the quadratic equation the sum of its roots is '-b', in other words x₁+x₂= -b

Answer: -b