A box of candy weighs 340.23 grams and costs $18.99. if 1 gram is approximately 0.03527 ounces, what is the unit price per ounce of the candy?

Answers

Answer 1
Answer: 340.23 / 0.03527 =9,646.44
$18.99 / 9,646.44 = .0019686
340.23 / 18.99 = 17.91
17.91 x .0019686 = .0352576

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In the circle, m arc BC = 72°. The diagram is not drawn to scale.

What is m angle BCP

Answers

Answer:

Measure of ∠BCP is 36°

Step-by-step explanation:

Given the circle in which measure of arc BC is 72°

we have to find the measure of angle BCP.

m∠BOC=∠2=72°

By theorem angle subtended at the centre is twice the angle formed at the circumference of circle.

∴ ∠2=2∠1 ⇒ 72=2∠1

⇒    ∠1=36°

By alternate segment theorem which states that

The angle formed between a chord and a tangent through one of the end points of chord is equals to angle in alternate segment.

⇒ ∠3=∠1=36°

Hence, measure of ∠BCP is 36°

Option D is correct

   

36 you take 72 and divide it by 2 and get 36

Scott has 1/3 of the computer games as Anish, and Anish has 1/2 as many games as Nick. Together they have 140 games. How many do they have each?Scott has......
Anish has......
Nick has......

Answers

Scott = Anish ÷ 3 or 1/3 Anish
Anish = Nick ÷ 2 or 1/2 Nick
S + A + N = 140
1/6 N + 3/6 N + 6/6 N = 10/6 N (140)
10/6 N = (140)
140 ÷ 10 = 1/6 N (14) = Scott
9/6 N (126) - 3/6 (42 = Anish) = N = 84
S = 14
A = 42
N = 84

CHECK?

14 = 1/3 of 42
42 = 1/2 of 84
14 + 42 + 84 = 140 :)
let x = # of computer games nick has
then
Anish has    1/2x games
and
Scot has  1/2*1/3   = 1/6x  games
 thus
1/6x + 1/2x + x  =  140
1/6x + 3/6x + x  = 140
10/6x = 140
10x =140* 6
   x       =      84  >        Nick
  1/2x    =    42  >    Anish
   1/6x    =   14    >    Scot

if I have a 71 percent in a class and I take a final worth 10 percent of my grade and fail. what would my grade be? thanks in advance.

Answers


I think you're asking for a numerical answer, but you didn't mention
your score on the final.

Since the final is worth 10% (one tenth) of the grade, that 71 that you
have going into the final is worth 9/10 of the grade. So the way you
calculate your overall average is

          Overall score = 1/10 of [ (71 x 9) + score on the final ] .

If you scored absolute zero on the final, your overall average would be

          Overall score = (1/10) x [ (71 x 9) + 0 ] = (1/10) (639) = 63.9% .

That's the lowest overall score for the class that you can have.

The highest overall score you could have would be if you got 100% on the final.
Then
         Overall = (1/10) x (639 + 100) = (1/10) x (739) = 73.9% .

If you got a 50% on the final, your overall would be

                         (1/10) x (639 + 50) = (1/10) x (689) = 68.9% .

In general, your overall score for the class, after the final, is going to be

           63.9%  plus  (1 tenth) of your score on the final.

Good luck !



61 percent that's the answer

What multiplies to -900 and adds to 5?

Answers

xy = -900
x + y = 5

     x + y = 5
x - x + y = -x + 5
           y = -x + 5

                                                xy = -900
                                      x(-x + 5) = -900
                                  x(-x) + x(5) = -900
                                       -x² + 5x = -900
                             -x² + 5x + 900 = 0
               -1(x²) - 1(-5x) - 1(-900) = 0
                          -1(x² - 5x - 900) = 0
                                       -1            -1
                               x² - 5x - 900 = 0
                               x = -(-5) ± √((-5)² - 4(1)(-900))
                                                      2(1)
                               x = 5 ± √(25 + 3600)
                                                  2
                               x = 5 ± √(3625)
                                             2
                               x = 5 ± 5√(145)
                                           2
                               x = 2.5 ± 2.5√(145)

                          x + y = 5
   2.5 ± 2.5 √(145) + y = 5
- (2.5 ± 2.5√(145)       - (2.5 ± 2.5√(145)
                                y = 2.5 ± 2.5√(145)
                          (x, y) = (2.5 ± 2.5√(145), 2.5 ± 2.5√(145))

The two numbers that add up to 5 and multiply to -900 are 2.5 ± 2.5√(145).

Which relationships hold true for the sum of the magnitudes of vectors u and v, which are perpendicular? a. ||u+v||=||u||+||v|| b. ||u+v||=sq rt(||u||^2+||v||^2) c. ||u+v||

Answers

The perpendicular are B) ||u+v|| = sqrt ||u||^2 + ||v||^2 and D) ||u+v|| less than ||u||+||v||

We have given that,

The relationships hold true for the sum of the magnitudes of vectors u and v,

We have determined which are perpendicular.

What is the magnitude of the vector?

The magnitude of a vector formula is used to calculate the length for a given vector (say v) and is denoted as |v|. So basically, this quantity is the length between the initial point and endpoint of the vector.

B) ||u+v|| = sqrt ||u||^2 + ||v||^2

AND

D) ||u+v|| less than ||u||+||v||

To learn more about the vector visit:

brainly.com/question/25705666

#SPJ2

it is

B) ||u+v|| = sqrt ||u||2 + ||v||2

AND

D) ||u+v|| less than ||u||+||v||

Bag a contains 3 white marveled and 2 marbles bag b contains 6 white marbles and 3 red marbles a person draws one marbles from each bag find the probability that both marbles are white

Answers

|\Omega|=5\cdot9=45\n|A|=3\cdot6=18\n\nP(A)=(18)/(45)=(2)/(5)