Answer:
1062.50
Step-by-step explanation:
if you're asking what is 15% off of $1,250 it is $1,062.50
Answer:
Sale price of TV will be $ 1062.5
Step-by-step explanation:
Using percentages we can find the sale price
15% = = 0.15
Multiplying the total by (0.15)(1250) = $ 187.5 that will be saved
1250 -187.5 = total sale price of the tv = $ 1062.5
GCF stands for Greatest Common factor. The greatest common factor(GCF) of the two numbers 15 and 64 is 1.
The greatest common factor or GCF is the common factor between two numbers.
Given to us
15 and 64
We know that the GCF is the common factor between the two numbers, therefore, in order to get the GCF of two numbers, we will write all the possible prime factors of the two numbers,
15 = 3 x 5 x 1
64 = 2 x 2 x 2 x 2 x 2 x 2 x 1
As we can see in the factors of the two numbers, the only common factor between the two numbers is 1.
Hence, the greatest common factor(GCF) of the two numbers 15 and 64 is 1.
Learn more about Greatest Common Factor:
$1.99/12
hope this helps
1 What is the theoretical probability that the family has two dogs or two cats? Describe how to use two coins to simulate which two pets the family has.
Flip both coins 50 times and record your data in a table like the one below. Result Frequency Heads,
Heads Heads, 9
Tails Tails,26
Heads Tails,26
Tails 15
Total 50
Based on your data, what is the experimental probability that the family has two dogs or two cats?
If the family has three pets, what is the theoretical probability that they have three dogs or three cats?
How could you change the simulation to generate data for three pets?
I just need the last questons answered thank you so much
Answer:
4 sets.
Step-by-step explanation:
We are asked to find the greatest number of sets you can make using 28 pens and 80 pencils.
To solve our given problem, we will find greatest common factor of 28 and 80.
Factors of 28: 1, 2, 4, 7, 14, 28.
Factors of 80: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80.
We can see that the greatest common factor of 28 and 80 is 4, therefore, you can make at-most 4 sets each having same number of pens and pencils.