Einstein calculated that ripples of gravity travel at exactly the speed of _____

Answers

Answer 1

Answer:

Answer:

299,792,458 m/s = speed of light

Explanation:

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Farmer Wilcox wants to reduce the wind velocity near his farm. He should _____.add dead leaves to his fieldscut down trees surrounding his fieldsplant trees around the perimeter of his fieldsirrigate his fields during dry seasons and droughts
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Complete the passage to describe wave interaction of diffracted waves.Diffracted waves of light interact with other waves and interference occurs. When the interference is constructive, this is shown as a

band on the screen. When the interference is destructive, this is shown as a

band on the screen.

Answers

Answer: When the interference is constructive, this is shown as a bright band on the screen. When the interference is destructive, this is shown as a dark band on the screen.

Explanation: edge 2021

Answer:Bright and Dark

Explanation:

Gaseous helium is in thermal equilibrium with liquid helium at 6.4 K. The mass of a helium atom is 6.65 × 10−27 kg and Boltzmann’s constant is 1.38066 × 10−23 J/K. Determine the most probable speed of a helium atom. Answer in units of m/s.

Answers

Answer:

162.78 m/s is the most probable speed of a helium atom.

Explanation:

The most probable speed:

$v_(mp)=\sqrt{(2K_bT)/(m)}$

$K_b$ = Boltzmann’s constant = $1.38066* 10^(-23) J/K$

T = temperature of the gas

m = mass of the gas particle.

Given, m = $6.65* 10^(-27) kg$

T = 6.4 K

Substituting all the given values :

$v_(mp)=\sqrt{(2* 1.38066* 10^(-23) J/K* 6.4 K)/(6.65* 10^(-27) kg)}$

$v_(mp)=162.78 m/s$

162.78 m/s is the most probable speed of a helium atom.

A 4-kilogram ball moving at 8 m/sec to the right collides with a 1-kilogram ball at rest. After the collision, the 4-kilogram ball moves at 4.8 m/sec to the right. What is the velocity of the 1-kilogram ball?

Answers

Conservation of momentum: total momentum before = total momentum after

Momentum = mass x velocity

So before the collision:
4kg x 8m/s = 32
1kg x 0m/s = 0
32+0=32

Therefore after the collision
4kg x 4.8m/s = 19.2
1kg x βm/s = β
19.2 + β = 32

Therefore β = 12.8 m/s

Frequency of a wave is 20 Hz. It travels with a speed of 5 m/sec. What is wavelength?

Answers

Answer:

omg i uses to know this answer

Explanation:

but I forgot

Which statements accurately describe atoms?

Answers

According to the statements made, the atoms were given names in the fifth century. All the others are untrue. Atoms can be divided, hence the previous claim that they are the smallest unit is also untrue. Atom splitting produces enormous amounts of energy, which is a topic of study in nuclear physics or other sciences. Additionally, because light particles are made up of atoms, they cannot be observed under a normal microscope.

What is an Atom?

An atom is a unit of matter that specifically characterizes a chemical element. One or more negatively charged electrons surround the core nucleus of an atom, which is made up of all of them. One or more protons and neutrons, which are comparatively heavy particles, can be found in the positively charged nucleus.

The fundamental units of matter are called atoms. Atoms make up anything that occupies space and has mass.

To know more about atoms :

brainly.com/question/1566330

#SPJ2

The answers from the statements provided is that the atoms were named in the fifth century. The others are false. Atoms can be divided as such the last statement of atom being the smallest unit is also false, splitting of atoms generates huge amount of energy studied in nuclear physics or sciences. It also cannot be seen through standard microscope as light particle itself is made up of atoms.

MARK ME BRAINIEST

How much energy ( in joules ) is released when 0.06 kilograms of mercury is condensed to a liquid at the same temperature ? A. 697.08 J
B. 17,705.1 J
C. 20,075.04 J
D. 51,302.88 J

Please include how you got your answer , thank you.

Answers

Answer:

B. 17,705.1 J

Explanation:

The hear released when the mercury condenses into a liquid is given by:

$Q=m \lambda_v$

where

m = 0.06 kg is the mass of the mercury

$\lambda_v$ is the latent heat of vaporization

For mercury, the latent heat of vaporization is $\lambda_v = 296 kJ/kg$ , so the heat released during the process is:

$Q=(0.06 kg)(296 kJ/kg)=17.76 kJ = 17,760 J$

So, the closest option is

B. 17,705.1 J

The energy ( in joules ) released when 0.06 kilograms ofmercury is condensed to a liquid at the same temperature is about 697.08 J. inother to solve this problem, should know the latent heat of fusion of mercurywhich is equal to about 11.4 kJ/kg and multiplying by mass of mercury.

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