Jacob is planting flowers in his yard. He Goes to a Nursery to purchase flowers he decided to purchase petunias and sunflowers petunias plant costs $2.99 with tax and each sunflower plant costs $2.79 with tax Jacob has $43.85 to purchase flowers. If he buys 10 petunia plants which inequality can be used to fine s, the number of sunflower plants that jacob can purchase.

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Answer 1

Answer: 11$ will be your answer

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Can someone please help me with this? Please explain

A case of Mountain Dew (24cans) costs $7.68. What is the unit price?

Answers

Here are the unit rates involved:

$7.68 / 1 case = $7.68 per case

$7.68 / 24 cans = $0.32 per can

1 case / $7.68 = 0.13 case per $

24 cans / $7.68 = 3.125 cans per $

And of course ...

24 cans / 1 case = 24 cans per case

1 case / 24 cans = 0.041666... case per can

Two buildings on opposites sides of a highway are 3x^3- x^2 + 7x +100 feet apart. One building is 2x^2 + 7x feet from the highway. The other building is x^3 + 2x^2 - 18 feet from the highway. What is the standard form of the polynomial representing the width of the highway between the two building?

Answers

Given:

Distance between two buildings = $3x^3- x^2 + 7x +100$ feet apart.

Distance between highway and one building = $2x^2 + 7x$ feet.

Distance between highway and second building = $x^3 + 2x^2 - 18$ feet.

To find:

The standard form of the polynomial representing the width of the highway between the two building.

Solution:

We know that,

Width of the highway = Distance between two buildings - Distance of both buildings from highway.

Using the above formula, we get the polynomial for width (W) of the highway.

$W=3x^3- x^2 + 7x +100-(2x^2 + 7x)-(x^3 + 2x^2 - 18)$

$W=3x^3- x^2 + 7x +100-2x^2-7x-x^3 -2x^2+18$

Combining like terms, we get

$W=(3x^3-x^3)+(- x^2 -2x^2-2x^2)+ (7x -7x)+(100 +18)$

$W=2x^3-5x^2+0+118$

$W=2x^3-5x^2+118$

Therefore, the width point highway is $2x^3-5x^2+118$ .

The correct standard form of the polynomial equation that represents the width of the highway between the two buildings is: $2x^3-5x^2+118$ .

Given:

Distance between the building: $3x^3-x^2+7x+100$

Building 1 distance from highway: $2x^2+7x$

Building 2 distance from highway: $x^3+2x^2-18$

To find the Width of the highway between two building:

Add the distances of the buildings from the highway.

Let's call the width of the highway "w"

Distance between the two buildings:

= $(2x^2 + 7x) + (x^3 + 2x^2 - 18)$

$= x^3+ 4x^2+7x-18$

Width of the highway:

$w = 3x^3-x^2+7x+100 -(x^3+4x^2+7x-18)\n\n= 3x^3-x^2+7x+100 -x^3-4x^2-7x+18\n\n = 2x^3-5x^2+118$

The polynomial equation is $2x^3-5x^2+118$ .

Learn more about polynomial equation here;

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Solve for z in terms of v, w, x, and y.
vy = -ZWx
Z =
I

Answers

Answer:

lots of letters

Step-by-step explanation:

A coat that originally sold for $369.00 is on sale at a 40% discount? How much will you pay for the coat?

Answers

The coat will cost $221.40. If you move a decimal two spaces to the left from 40% (.40) and multiply it by $369.00, you'll get $147.60. You then subtract $147.60 from $369.00 and get $221.40, the final price of the coat.

The best way to work out something like this is to find out what ten percent is. The way in which you do this is to divide the price by 10. This gives you $36.90. Therefore, this is equal to ten percent. As you're looking for forty percent, you need ot mulitply the answer by four, and this gives you $147.60. You then have to subtract $147.60 from $369
$369-147.60= $221.40
I deleted my answer and put the correct one- sorry about that, my calculator seems to have a mind of its own :)

I need help in doing question 1B please.