MATHEMATICS HIGH SCHOOL

A car travels a distance of 110 miles in a time or 2.8 hours what Is its average speed rounded to 1dp

Answers

Answer 1
Answer: 110/2.8=39.3 miles per hour
Answer 2
Answer:

Answer:

39.3

its simple

Related Questions

Simplify (x^2y)^3.ASAP please
Answer this question to get marked as barinliest!!!!
Which expression represents 100 divided by an unknown number?A. 100 • p B. 100 ÷ p C. 100 – p D. 100 + p
Which statement is true about Ralph’s skiing goal?
3^x - 3^(x-1) = 18 then 4^x is equal to

10(x+3)=9
mmmmmmmmmmmmmmmmm

Answers

divide both sides by 10
x+3=0.9
minus 3
x=2.1
Solutions 

Divide both sides by 10

x+3=9 / 10

Subtract 3 from both sides

x=9 / 10 −3

 Simplify 9 / 10 −3 to −21 / 10

x=−21 / 10


Decimal = -2.1

Create a quadratic polynomial function f(x) and a linear binomial in the form (x − a).Show all work to evaluate f(a) using the function you created.

Answers

our quadratic polynomial function is:

f(x) = 4x^2 + 2x + 5

our linear binomial form is:
x - a = -2
hence:
a = x + 2

and so we have:
f(x) = 4x^2 + 2x + 5
f(a) = 4(x + 2)^2 + 2(x + 2) + 5
= 4(x^2 + 4x + 4) + 2x + 4 + 5
f(a) = 4x^2 + 18x + 25

The graph of which function has a minimum located at (4, –3)?f(x) = x2 + 4x – 11
f(x) = –2x2 + 16x – 35
f(x) = x2 – 4x + 5
f(x) = 2x2 – 16x + 35

Answers

Answer:

None of the options is the answer to the question

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

f(x)=a(x-h)^(2)+k

where

(h,k) is the vertex of the parabola

case A) we have

f(x)=x^(2)+4x-11

In this case the x-coordinate of the vertex will be negative

therefore

case A is not the solution

case B) we have

f(x)=-2x^(2)+16x-35

This case is a vertical parabola open downward (the vertex is a maximum)

The vertex is the point (4,-3)but is not a minimum

see the attached figure

therefore

case B is not the solution

case C) we have

f(x)=x^(2)-4x+5

Convert into vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

f(x)-5=x^(2)-4x

Complete the square. Remember to balance the equation by adding the same constants to each side

f(x)-5+4=(x^(2)-4x+4)

f(x)-1=(x^(2)-4x+4)

Rewrite as perfect squares

f(x)-1=(x-2)^(2)

f(x)=(x-2)^(2)+1 --------> vertex form

The vertex is the point (2,1)

therefore

case C is not the solution

case D) we have

f(x)=2x^(2)-16x+35  

Convert into vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

f(x)-35=2x^(2)-16x

Factor the leading coefficient

f(x)-35=2(x^(2)-8x)

Complete the square. Remember to balance the equation by adding the same constants to each side

f(x)-35+32=2(x^(2)-8x+16)

f(x)-3=2(x^(2)-8x+16)

Rewrite as perfect squares

f(x)-3=2(x-4)^(2)

f(x)=2(x-4)^(2)+3 --------> vertex form

The vertex is the point (4,3)

therefore

case D is not the solution

The answer to the question will be the function

f(x)=2x^(2)-16x+29

18 • 3 32 pls I will thank you it’s worth 10 points

Answers