The product of 2 square root 5 (13 + square root 2) in simplified form is 26√5 + 2√10
From the question, we have the following parameters that can be used in our computation:
2 square root 5 (13 + square root 2)
Express as products
So, we have
2√5 * (13 + √2)
Open the brackets
So, we have
2√5 * (13 + √2) = 2√5 * 13 + 2√5 *√2
Multiply the radicands
So, we have the following
2√5 * (13 + √2) = 2√5 * 13 + 2√10
Evaluate the products
So, we have the following
2√5 * (13 + √2) = 26√5 + 2√10
Hence, the solution is 26√5 + 2√10
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Answer:
i'm assuming it's 2*√5(13+√2) so 2√10+26√5
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
el 2 al cuadrado es 4 si le restas su mitad(2) tu resultado seria 2
Answer: 2
Step-by-step explanation : el 2 al cuadrado es 4 si le restas su mitad(2) tu resultado seria 2 Espero que ayude Ten un día maravilloso :)
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The area of a triangle with vertices at (0, −2) ,(8, −2) and (9, 1) is 12 square units
Solution:
Given, vertices of the triangle are A(0, -2), B(8, -2) and C(9, 1).
We have to find the area of the given triangle.
The area of triangle when vertices are given is:
Here in our problem,
Now, substitute the above values in the formula:
Hence, the area of the triangle is 12 square units.