Jan has $37.50. tickets to concert cost $5.25 each. how many tickets can she buy

Answers

Answer 1
Answer: x-\ number\ of\ tickets\n\nTo\ find\ number\ of\ tickets\ divide\ all\ money\ that\ he\ has\ and \n next\ divide\ by\ cost\ of\ one\ ticket\n\nx=(37.5\$)/(5.25\$)=7.14....\n\nHe\ can\ buy\ 7\ tickets.

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Can anybody help me with this question?

Answers

For number 16 we need to write the data as a ratio then convert to a unit rate (amount per 1)...

308/14 = x/1

Cross multiply

14x = 308
x = 308/14
x = 22

So the fuel efficiency is
22 miles per 1 gallon or

22/1

For number 17, since the car was driven at 48 mph, we just have to divide distance driven by speed to get how long it took...

288 miles ÷ 48 mph =

6 hours

How many points are shared by two perpendicular lines? but two parallel lines?

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Two perpendicular lines intersect once, to form a right angle. Therefore, on point is shared by two perpendicular lines. since parallel lines never touch, there are NO points shared between the two lines.

Please help me with this ! Write a short explanation if it can but not necessary.

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Unfortunately, we can't draw it for you, as the diagram is in your book!  To create the line, simply find some points on the line and connect them, extending the line past each point in the same direction (you can use a ruler to help with this).  To find points on the line, plug in values for x to the equation and find the corresponding y-value.

What are the square roots of 144 over 256 ?A.
minus 12 over 16 and 12 over 16

B.
minus 12 over 18 and 12 over 18

C.
minus 9 over 16 and 9 over 16

D.
minus 72 over 128 and 72 over 128

Answers

You can get the solution by just testing.
Let's start with A:
12*12=144
16*16=256

Now you know that A is the correct answer.

I need help with everything please tell me how to show work and the answer

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All the answers attracted in the photo with working
This answer is correct above

What is 0.03703703703 as a fraction

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n=0.\dot { 0 } 3\dot { 7 } \n \n 1000n=37.\dot { 0 } 3\dot { 7 } \n \n 1000n-n=37

\n \n 999n=37\n \n n=\frac { 37 }{ 999 } \n \n n=\frac { 37 }{ 37 } \cdot \frac { 1 }{ 27 } \n \n \therefore \quad n=\frac { 1 }{ 27 }
x=0.\overline{037}\n1000x=37.\overline{037}\n1000x-x=37.\overline{037}-0.\overline{037}\n999x=37\nx=(37)/(999)=(1)/(27)