Genes-Adistancesequenceofnucleotides.
4PCl5(g) → P4(s) + 10Cl 2(g) ΔH = 3438 kJ
The value of ΔH will be 249.75 KJ.
To obtain the reaction :
PCl5(g) → PCl3(g) + Cl2(g)
We have to add the given reactions and then divide it by 4.
(i) adding the reactions
P4(s) + 6Cl2(g) → 4PCl3(g) ΔH = -2439 kJ
4PCl5(g) → P4(s) + 10Cl 2(g) ΔH = 3438 kJ
we get:
4PCl5(g) → 4PCl3(g) + 4Cl2(g), ΔH = 3438 - 2439
(ii) dviding by 4
PCl5(g) → PCl3(g) + Cl2(g) , ΔH = (3438 - 2439)/4
ΔH = 249.75 kJ is the required enthapy.
Learn more about enthalpy:
Answer:
The value of for the desired reaction will be 249.75 KJ.
Explanation:
The desired reaction is shown below
The desired reaction can be obtained by adding the given reactions and then dividing both sides by 4.
Net Enthalpy change for the desired reaction
Usually a ball would roll toward the side that's lower, so if you had a ramp and put it on the side that was lower, then the ball would change direction and go the opposite direction
O3
OCN-
Co2
Cs2
PLZ help
Answer:
False
Explanation:
i tried true and it didnt work.
Answer:
Transcription
Explanation: