He needed 4 1/2 bunches So 5 bunches
B.(7.5, –3.5) and (7.5, 3.5)
C.(7.5, 1.2) and (7.5, 2.3)
D.(7.5, –3.5) and (7.5, 7)
The points between whom the distance is 3.5 units apart are (7.5, 1.2) and (7.5, -2.3).
Given is to find the points between whom the distance is 3.5 units apart.
Using the distance formula for the points (7.5, 1.2) and (7.5, -2.3), we get-
d² = (- 2.3 - 1.2)² + (7.5 - 7.5)²
d² = (3.5)²
d = 3.5 units
Therefore, the points between whom the distance is 3.5 units apart are (7.5, 1.2) and (7.5, -2.3).
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5 3/5 + 2 1/10
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Answer:
1 and 2
Step-by-step explanation: