A.) 1.5 2.5 -2 -3.5
-1 2 -3 0
B.) -1.5 -2.5 2 3.5
1 -2 3 0
C.) -4.5 -7.5 6 10.5
3 -3 9 0
D.) -3.5 -5.5 4.5 7. 5
2.5 -4.5 6.5 0.5
X + 60°
X=
20
40
80
i think its C because don't you have to add the numbers together
The answer is 40 degrees :]
Answer: For E2020 is B
P(tulip)= 37/86
The x represents time in seconds while y represents the depth of the submarine and the equation with constraint will be y = 10.5x + 50.
Determine the known quantities and designate the unknown quantity as a variable while trying to set up or construct a linear equation to fit a real-world application.
In other words, an equation is a set of variables that are constrained through a situation or case.
As per the given,
The slope m = rate of descending = 10.5 ft/s
The y-intercept c = initial depth of submarine = 50 ft
Thus, y = mx + c converts as,
y = 10.5x + 50
Hence "The x represents time in seconds while y represents the depth of the submarine and the equation with constraint will be y = 10.5x + 50".
For more about the equation,
#SPJ5
Answer:
The constraints on the x-values or independent variable – time are:
0 s < time < 5 s
The constraints on the y-values or dependent variable – Depth are:
50 ft < Depth (below sea level) < 102.5 ft
Step-by-step explanation:
Boundary restrictions that are placed upon the variables in an equation are called the Constraints.
The x-values are the independent variables in an equation and in our case it is time.
The y-values are the dependent variables in an equation and in our case it is depth (below the sea level).
The rate of descend provided in the question is constant and is equal to 10.5 ft/s.
We can write our equation of Depth as follows:
Depth (below sea level) = 50 + 10.5*(time)
The constraints on the x-values or independent variable – time are:
0 s < time < 5 s
We can put the boundary values of x variable constraints in the equation of Depth to find the constraint on y-values or dependent variable.
Depth (below sea level) = 50 + 10.5*(time)
Depth (below sea level) = 50 + 10.5*(0), at time 0 s
Depth (below sea level) = 50 ft
Depth (below sea level) = 50 + 10.5*(5), at time 5 s
Depth (below sea level) = 102.5 ft
So the constraints on the y-values or dependent variable – Depth are:
50 ft < Depth (below sea level) < 102.5 ft
Answer:
use a algebra caculator
Step-by-step explanation:
Answer:
-4.125
Step-by-step explanation:
5/8 - 3/4 (8-1/2 ) + 1 = - 33/8 = -4 1/8
Answer:
yes they intersect
point of intersection is (-17.6,38.2,18.6)
Step-by-step explanation:
the direction vector for L2 is given but for L1 it is not given.
Let's first find the direction vector for the L1 as;
from points Q1 and Q2 we can find the direction vector by subtracting there corresponding coordinates (x,y,z) as;
-1-(-2), 5-7, 2-3
direction vector for L1= [1,-2,-1]k
Now the equation for L1 is;
x1=-2+k
y1=7-2k
z1=3-k
direction vector for L2 is =[−6, 3, 6]T
So the equation for the L2 is;
x2=-8-6T
y2=4+3T
z2=9+6T
If these points are intersecting then there x coordinates must be equal, y coordinates must be equal and z coordinates must also be equal as;
x1=x2; y1=y2; z1=z2;
-2+k=-8-6T.......(a)
7-2k=4+3T.......(b)
3-k=9+6T.........(c)
subtracting (a) and (c) we get
-2+k=-8-6T
-( 3-k=9+6T)
______________
-5+2k=-17-12T.......(d)
adding (b) and (d) we get
7-2k=4+3T
-5+2k=-17-12T
______________
-2=13-9T
T=1.6 putting in (a) we get k as;
-2+k=-8-6(1.6)
k=-15.6
putting T and k, if it satisfy the equation then they intersect
(c)=3-(-15.6)=9+6(1.6)
18.6=18.6 satisfied.
thus they intersect each other and their point of intersection is
x=-2-15.6
x=-17.6
y=7-2(-15.6)
y=38.2
z=3-(-15.6)
z=18.6
point of intersection is (-17.6,38.2,18.6)