A recipe includes 8 cups of flour and 2/3 third cups of sugar right the ratio of the amount of flour to the amount of sugar as a fraction in simplest form

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Answer 1

Answer: Its 8:2/3, we can write it as $(8)/( (2)/(3) ) =8 *(3)/(2) = (8*3)/(2) = (24)/(2)= (12)/(1)$
Now we can back to 12:1 - its the result

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Gloria has a lunch account in the school cafeteria. The balance, f(x), in her account can be represented by the function f(x) = –1.50x + 40, where x is the number of meals purchased. Suppose –1.50 changed to –2.75. What does this mean in the context of the problem?
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Given the line 2x - 3y - 5 = 0, find the slope of a line that is perpendicular to this line.

8+4i
———
2i

please show work!!

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Please brainliest this what Siri said

Help pplssssss 3e7374743

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The answer is -11/8 in fraction form
-1.37 in decimal

Jose painted a square shaped mural. The length of each side of the canvas was 1 1/3 yards. What is the area of the mural in square yards?

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area of a square : s * s
1 1/3 * 1 1/3
4/3 * 4/3
= 16/9
=1 and 5/9 square yards or y^2

Find the slope of (-5,28) and (-4,23)

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Answer:

Step-by-step explanation:

The first term of an arithmetic sequence is -5, and the tenth term is 13. Find the common difference.a. 8/9
b. 2

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Hello,

Answer B
$a_(0)=-5\na_(9)=a_(0)+9*r\n13=-5+9*r\nr= (18)/(9)=2$

Identify whether each value of x is a discontinuity of the function by typing asymptote, hole, or neither. 5x/ x3 + 5x2 + 6x

Answers

Answer:

Function is discontinuous at

x=0 (Hole)

x=-3 (Vertical asymptote)

x=-2 (Vertical asymptote)

Step-by-step explanation:

Given: $f(x)=(5x)/(x^3+5x^2+6x)$

We need to identity the discontinuity of the function. As we know function is discontinuous where it is not defined.

So, The function is discontinuous at hole, asymptote and break point.

$f(x)=(5x)/(x^3+5x^2+6x)$

$f(x)=(5x)/(x(x^2+5x+6))$

$f(x)=(5x)/(x(x+3)(x+2))$

For hole, we will cancel like factor from numerator and denominator.

At x=0 we get hole.

For vertical asymptote, we set denominator to 0

x+3=0 and x+2=0

Vertical asymptote:

x=-3 and x=-2

Function is discontinuous at

x=0 (Hole)

x=-3 (Vertical asymptote)

x=-2 (Vertical asymptote)

Answer:

asymptote

hole

neither

Other Questions

"What temperatures are included in the temperature danger zone? A) 0°F (-18°C) to 41°F (5°C) B) 32°F (0°C) to 100°F (38°C) C) 41°F (5°C) to 140°F (60°C) D) 141°F (61°C) to 240°F (116°C)."

PLEASE Find the equation of the line............................perpendicular to the line y= 5x -1 and passes through the points (10,8)

PLS HELP SHOW ALL YOUR WORKING OUT :D

Slope = -5 and goes thorough point (0, 2)