According to the Fundamental Theorem of Algebra, how many roots exist for the polynomial function?

Answers

Answer 1
Answer:

Answer:

5

Step-by-step explanation:


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MATH 1325 – EXAM 4 NAME: ______________________________ SHOW ALL WORK. ANSWERS WITHOUT WORK WILL RECEIVE NO CREDIT. YOU MUST USE A PENCIL. READ ALL DIRECTIONS. POINTS WILL BE DEDUCTED FOR FAILURE TO FOLLOW DIRECTIONS. TRUE/FALSE – WRITE THE WORD THAT BEST DESCRIBES THE GIVEN STATEMENT BY WRITING EITHER "TRUE" OR "FALSE" IN THE SPACE PROVIDED TO THE LEFT OF THE PROBLEM. __________ 1. THE ABSOLUTE MAXIMUM OF A FUNCTION ALWAYS OCCURS WHERE THE DERIVATIVE HAS A CRITICAL FUNCTION. __________ 2. IMPLICIT DIFFERENTIATION CAN BE USED TO FIND dy dx WHEN x IS DEFINED IN TERMS OF y . __________ 3. IN A RELATED RATES PROBLEM, THERE CAN BE MORE THAN TWO QUANTITIES THAT VARY WITH TIME. __________ 4. A CONTINUOUS FUNCTION ON AN OPEN INTERVAL DOES NOT HAVE AN ABSOLUTE MAXIMUM OR MINIMUM. __________ 5. IN A RELATED RATES PROBLEM, ALL DERIVATIVES ARE WITH RESPECT TO TIME. MULTIPLE CHOICE – CHOOSE THE ONE ALTERNATIVE THAT BEST COMPLETES THE STATEMENT OR ANSWERS THE QUESTION BY CIRCLING THE CORRECT LETTER. 6. FIND THE MAXIMUM ABSOLUTE EXTREMUM AS WELL AS ALL VALUES OF x WHERE IT OCCURS ON THE SPECIFIED DOMAIN

Answers

Answer: Please see explanation column for answers. Also check number 6, its question is incomplete.  i used an assumed function, incase its not the same function with the one omitted, just follow steps

Step-by-step explanation: Questions 1-5 do not need any step by step explanation, its purely straight forward but Question 6 involves step by step explanation but  is not a complete question, though i used an assumed function.

FALSE   ---> 1. THE ABSOLUTE MAXIMUM OF A FUNCTION ALWAYS OCCURS WHERE THE DERIVATIVE HAS A CRITICAL FUNCTION. ___TRUE_____-->__ 2. IMPLICIT DIFFERENTIATION CAN BE USED TO FIND dy/dx WHEN x IS DEFINED IN TERMS OF y .

TRUE__--->3. IN A RELATED RATES PROBLEM, THERE CAN BE MORE THAN TWO QUANTITIES THAT VARY WITH TIME.

_FALSE  ---> 4. A CONTINUOUS FUNCTION ON AN OPEN INTERVAL DOES NOT HAVE AN ABSOLUTE MAXIMUM OR MINIMUM.

____TRUE__--->____ 5. IN A RELATED RATES PROBLEM, ALL DERIVATIVES ARE WITH RESPECT TO TIME.

6. FIND THE MAXIMUM ABSOLUTE EXTREMUM AS WELL AS ALL VALUES OF x WHERE IT OCCURS ON THE SPECIFIED DOMAIN

----Incomplete question Please.

But assuming the function---- f(x)= x³ -3x+1

 for (E)=(0,3)

step 1= let us use the power rule to find derivative of   f(x)= x^3 -3x+1

we will have f¹ (x) = 3x² -3

The critical values occurs when  3x² -3 = 0

which makes x=⁺₋1

As can be seen 3x² -3 = 0

                         3x²=3

                          x²=3/3=1

                       x= ⁺₋1

step 2=Now x= -1 cannot be considered because it is not in the interval  of the critical values (0,3)

therefore we consider x=1

step 3=The absolute extremes occurs at x=0, x=1, x=3 forf(x)= x³ -3x+1

when x=0,  f(0)= 0³-3(0)+ 1= 1

         x=1    f(1)=1³-3(1) +1=  -1

         x=3    f(3)= 3³ -3(3)+1= 19

Absolute minimum at x=1 has absolute value of-1

Absolute maximum of x=3 has absolute value of 19

How many times does 36 go into 180

Answers

It would be 5. Hope this helps. :)
the answer is 5 hoped that helped

What is .5 ( 5 repeating) in a fraction ?

Answers

Hey there! I'm happy to help!

Let's say that our fraction is x.

x=0.5555555...

Let's get rid of the repeating stuff. If you multiplied x by 10, the fraction would be equal to 5.5555555.....

x=0.55555555....

10x=5.5555555.....

What if we subtracted the first equation from the second? Then all of the repeating stuff would be gone!

9x=5

We divide both sides by 9.

x=5/9.

Have a wonderful day! :D

Which equation represents a line that passes through -2,4 and has a slope of 2/5 need help Now

Answers

Answer:

y = 2/5x + 24/5

Step-by-step explanation:

y - 4 = 2/5(x - (-2))

y - 4 = 2/5(x +2)

y - 4 = 2/5x + 4/5

y = 2/5x + 4/5 + 4

y = 2/5x + 24/5

Which inequality's solution is graphed here? A) 3x + 5 > 3 Eliminate B) 3x - 5 > 3 C) 5x + 3 > 3 D) 5x - 3 > 3

Answers

The equation of line passing through points (-4, 1) and (2, 3) will be

3y = x + 7

What is the general equation of a Straight line inequality?

An inequality in mathematics compares two values or expressions, showing if one is less than, greater than, or simply not equal to another value. The general equation of a straight line inequality is -

[y] < [m]x + [c]

[y] > [m]x + [c]

[y] ≥ [m]x + [c]

[y] ≤ [m]x + [c]

where -

[m] → is slope of line which tells the unit rate of change of [y] with respect to [x].

[c] → is the y - intercept i.e. the point where the graph cuts the [y] axis.

The equation of a straight lineinequality can be also written as -

Ax + By + C > 0

By > - Ax - C

y > (- A/B)x - (C/A)

Given is inequality's solution graphed [Refer to graph attached].

The inequality whose solution is graphed is -

5x + 3 > 3

On solving -

5x + 3 > 3

5x + 3 - 3 > 3 - 3

5x > 0

x > 0

Therefore, the inequality whose solution is graphed is

5x + 3 > 3

(Refer the image attached, for reference)

To solve more questions on inequalities, visit the link below -

brainly.com/question/1782515

#SPJ5

Here is the graph 
The Answer is C) 5x + 3 > 3

A dolphin ate 2604 pounds of fish during the 31 days in march. What is the average amount of fish the dolphin ate per day.

Answers

To find the average of something you add up all of the data points (in this case it would be how many pounds offish were eaten per day but this is already done for us) then you would divide by the number of points you have (the number of days which is 31). So all you have to do is 2604/31. This equals 84 pounds of fish per day on average.

the dolphin ate

2604 lbs of fish in 31 days

this can also be written as

2604/31

we want the denominator to be 1, since the denominator represents days

to do this, we can divide 31 by 31. but we must do the same to the numerator

2604 ÷ 31 = 84

so our new fraction is

84/1

so per day, the dolphin ate 84 pounds of fish