3. Factor.
9x2 + 15x

(Points : 1)       x(3x + 5)
      3x(3x + 5)
      9x(x + 5)
      3x2(3x + 5)
Question 4.4. Factor.

20mn − 30m

(Points : 1)       2m − 3
      10m(2n − 3)
      10mn(2m + 3n)
      10n(2m − 3)

Question 5.5. Factor.

8x2y2 − 4x2y − 12xy

(Points : 1)       4(2xy − 4x2y − 12xy)
      4(8x2y2 − x − 12xy)
      4x2y2(2xy − xy −3)
      4xy(2xy − x − 3)

Answers

Answer 1

Answer: It seems that some the work is already here, but I'd be glad to!! So for #3 which is 9x^2+15x, we can factor out both a 3 and an x (3x) so we know that 3x * 3x =9x^2 and 3x * 5 = 15x so once we take the 3x out of the equation, we are left with 3x(3x+5) and that's as far as you can factor.
For #4, we see that the common factor is 10m because 10m * 2n = 20mn and 10m * 3 = 30m so once we take 10m out of the original, it becomes 10m(2n-3)
For #5, this one the common factor is 4xy because 4xy * 2xy=8x^2y^2 and 4xy*x= 4x^2y and 4xy*3=12xy so once we take the 4xy out of the equation, it becomes 4xy(2xy-x-3)
Hope this helps!

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Answers

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What is the quotient (125 – 8x3) ÷ (25 + 10x + 4x2)?–2x + 5
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Answers

For this case we have the following expression:

$(125-8x^3)/(25+10x+4x^2)$

Factoring the numerator we have:

$(-(2x+5)(4x^2+10x+25))/(25+10x+4x^2)$

Rewriting the denominator we have:

$(-(2x+5)(4x^2+10x+25))/(4x^2+10x+25)$

Canceling similar terms we have:

$-(2x+5)$

$-2x-5$

Answer:

The quotient of the division is given by:

$-2x-5$

If you would like to solve (125 - 8x^3) / (25 + 10x + 4x^2), you can do this using the following steps:

(125 - 8x^3) / (25 + 10x + 4x^2) = - ((2x - 5) * (4x^2 + 10x + 25)) / (4x^2 + 10x + 25) = - (2x - 5) = - 2x + 5

The correct result would be - 2x + 5.

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Answers

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Answers

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Answers

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