Is 18.797 bigger than 18.866

Answers

Answer 1

Answer: No it is less than 18.866.

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A plumber has a copper pipe 0.9 meter long. He cuts the pipe into 4 equal pieces. Find the length of each piece of meters. Rounds your answer to the nearest tenth of a meter.

Answers

0.9m = 90cm

90÷4 = 22.5cm = 0.225m ≈ 0.2m

Painting is 2 in by 1.5 in. Scale is 1 in:40 cm. What are the dimensions of the original painting?

Answers

Answer:

80 cm by 60 cm

Step-by-step explanation:

To solve this we know that the scale is 1 In: 40 Cm since our painting is already in inches all we have to do is multiply the inches by 40, so 2 inches * 40 is 80 and 1.5 * 40 is 60 and now all we do is turn the units into centimeters and we are done!

Which pair of angles is a linear pair? A. Angle VQT and Angle SQT
B. Angle WQV and angle VQU
C. Angle RQS and angle SQT
B. Angle SQT and Angle TQU

Please respond with the correct answer, and how you got the answer :)

Answers

Hey Jasmine! So a linear pair must equal 180 degrees, Option A makes the most sense to me because if you were to combine both the angles together they would equal 180 degrees, all of the other options would be skewed from 180

What is this sum about like 3×3 what is that pls tell me

Answers

3x3=9

hope this helps

3x3=9 that's my answer.

Ahmed found the volume of a cone having both a height and a diameter of 6 centimeters. His work is shown below.What was Ahmed’s first error?
In Step 1, the radius should be found by multiplying the diameter by 2.
In Step 2, the formula 2pi r should be used to find the area of the circle.
In Step 3, the resulting area should be in terms of pi
In Step 4, the units of the resulting volume should be cm^2

Answers

Whenever we are given with the diameter of any such figure ,

to find the radius , we divide the diameter by 2.

We know that

Diameter = 2 * radius

Radius = Diameter /2

In the question it says the in first step that

the radius should be found by multiplying the diameter by 2

, this is the first error

It should be that

the radius should be found by dividing the diameter by 2

Answer:

Step-by-step explanation:

I dont have time sorry comment kf younwantnme tk explain

Anybody know the right answer?

Answers

Quadrant I : cot(x) > 0 → -cot(x) < 0

Quadrant II : cot(x) < 0 → -cot(x) > 0

Quadrant III : cot(x) > 0 → -cot(x) < 0

Quadrant IV : cot(x) < 0 → -cot(x) > 0

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$a)\ \left((11\pi)/(6),\ -\sqrt3\right)\n\n(11\pi)/(6)\in\text{Quadrant IV, then -cot(x)} > 0,\ \text{we have}\ -\cot(11\pi)/(6)=-\sqrt3 < 0$

Answer: a)

$b)\n(2\pi)/(3)\in\text{Quadrant II},\ -\cot(x) > 0,\ \text{we have}\ (\sqrt3)/(3) > 0\n\nc)\n(5\pi)/(4)\in\text{Quadrant III},\ -\cot(x) < 0,\ \text{we have}\ -1 < 0\n\nd)\n(4\pi)/(3)\in\text{Quadrant III},\ -\cot(x) < 0,\ \text{we have}\ -(\sqrt3)/(3) < 0$

We know that one answer is only true, so we did not check the correctness of the cotangent value, only to the number sign

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