Sodium has 11 electrons, and in its ground state, 8 of these electrons are located in the second principal energy level.
The total number of electrons in the second principal energy level of a sodium atom in the ground state can be determined by understanding the electron configuration of sodium.
Sodium (Na) has an atomic number of 11, which means it has 11 electrons. In the ground state, these electrons are distributed in various energy levels. The second principal energy level, often denoted as n=2, can hold a maximum of 8 electrons. The first energy level, n=1, can hold a maximum of 2 electrons.
To find the number of electrons in the second energy level, we first fill the first energy level with 2 electrons and then place the remaining 9 electrons in the second energy level. However, since the second energy level can only hold 8 electrons, sodium's electron configuration in the ground state is 2-8-1, where 2 electrons are in the first energy level, 8 electrons are in the second energy level, and 1 electron is in the third energy level.
So, there are 8 electrons in the second principal energy level of a sodium atom in the ground state.
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B. stronger attraction for electrons
C. smaller number of first-shell electrons
D. larger number of first-shell electrons
Answer:
The quantum numbers n = 3 and l = 0 correspond to a specific type of orbital within the third principal energy level (n = 3) of an atom.
When l = 0, it corresponds to the s orbital. So, the orbital designated by the quantum numbers n = 3, l = 0 is the 3s orbital. The 3s orbital is spherically symmetrical and has a single orientation within its energy level.
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