MATHEMATICS HIGH SCHOOL

PLZZZ HELP WILL MARK BRAINLIEST What is the simplified value of the expression below?4.5-59
0.2x3-02
A) -3.5
B) -2.4
C)2.4
D)3.5
PLZZZ HELP WILL MARK BRAINLIEST What is the simplified value - 1

Answers

Answer 1
Answer:

Answer:

-3.5

Step-by-step explanation:
Answer 2
Answer:

Answer:

The answer is D

Step-by-step explanation:

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Change the fraction 3 /4 to a percent. A. 63% B. 133% C. 75% D. 34%

Answers

3/4 to be converted in fraction.
Based on the choices, let's solve for the percentage form of 3/4
=> First divide 3 by 4
=> 3 / 4 =  0.75
0.75 to be converted to percentage form
=> 0.75 * 100% = 75%
The answer is c.

Maureen has a net spendable income of $2,100 per month. She sets up the following transportation budget for herself. Transportation (15% - 20%) 350 a. Car payments 150
b. Gas/Oil 120
c. Insurance 60
d. License/Registration 2
e. Taxes 5
f. Maintenance/Repair 50
what has she done wrong?


A: She budgeted more than the maximum recommended amount of money for transportation.

b: She has more money in the main category than she budgeted for in the subcategories.

c: She has more money in the subcategories than she budgeted for in the main category.

d: She budgeted less than the minimum recommended amount of money for transportation.

Answers

Answer:

c. She has more money in the subcategories than she budgeted for the main category

Explanation:

First, let's check the budget she set for the main category:

We are given that Maureen has net spendable income of $2,100.

The minimum amount she budgeted for transportation is 15% which can be calculated as follows:

Minimum budget for transportation = 15% * 2,100 = 0.15 * 2,100 = $315

Then, let's check her subcategories:

$150 for car payments, $120 for gas/oil, $60 for insurance, $2 for licence/registration, $5 taxes and $50 for maintenance/repair

This means that:

Minimum amount she will spend = 150 + 120 + 60 + 2 + 5 + 50 = $387

Now, let's compare:

Minimum budget set by Maureen is $315

Minimum amount she needs to spend on subcategories is $387

It is obvious that the minimum amount she needs is higher than the minimum budget she set for transportation, i.e., she has more money in subcategories than she budgeted in the main category.

This means that she needs either to increase her minimum budget for transportation or to lower the minimum amount she needs to spend.

Hope this helps :)

Answer:

Option C is correct.

Step-by-step explanation:

Given information is :

Net monthly spendable income = $2100

Transportation budget set up = $350 that lies between 15 to 20 percent of the net spendable.

Now adding her subcategories budget we get:

150+120+60+2+5+50=387

But Maureen has set $350 for this category. It clearly shows that the subcategories have more budget. So, either Maureen can increase her main category budget(this option is not given) or she can cut few of her subcategory budget to fall under $350.

Hence, Option c: She has more money in the subcategories than she budgeted for in the main category - is correct.

A closet contains 5 shirts, 8 skirts, and 3 pairs of shoes. How many possible outfit combinations are there?

Answers

actually the answer is 120, apex:)

Answer:

120 combos

Step-by-step explanation:

VOTE ME FOR BRAINILEST.

I need help please someone explain me how to do it

Answers

Hello,

\lim_(n \to -\infty) {-x^7+bx^3+c} = -(-\infty) =\infty
(we don't  take  care  of lest powers , only the upper power)

Answer C

Solve for x 4=(-8)+3x

Answers

Let's solve your equation step-by-step.4=−8+3xStep 1: Simplify both sides of the equation.4=3x−8Step 2: Flip the equation.3x−8=4Step 3: Add 8 to both sides.3x−8+8=4+83x=12Step 4: Divide both sides by 3.3x3=123x=4Answer:x=4
4=(-8)+3x
4+8=(-8+8)+3x
12=3x
12/3=4
X=4

Hope that helps!!

Evaluate the integral: \[\int\limits_{}^{}ye ^{0.2y}dy\]
The problem we are having is the antiderivative of
\[e ^{0.2y}.\] We decided to split the problem into:
u = y
\[uv = e^{0.2y}\]
We just aren't sure where to go from here. Help?

Answers

\int\limits_{}^{}ye ^(0.2y)dy\n\nu=y,du=dy\ndv=e ^{(y)/(5)}dy,v=\int\limits_{}^{}e ^{ (y)/(5) }dy=5e ^{ (y)/(5) }\n\n \int\limits_{}^{}ye ^{(y)/(5) }}dy=uv- \int\limits {v} \, du=y 5e ^{ (y)/(5) }-\int\limits {5e ^{ (y)/(5) }} \, dy= 5ye ^{ (y)/(5) }-25e ^{ (y)/(5) }=5e ^{ (y)/(5) }(y-5)
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