MATHEMATICS HIGH SCHOOL

100 points with work

Answers

Answer 1

Answer:

Answer:

jacky 12 809 n-t

Step-by-step explanation:

Answer 2

Answer:

Answer:

he said it not me

Related Questions

(5,0) is a solution to the equation y = 5x + 5 Question 11 options: True False
A square measures 8 inches on each side. What is its area rounded off to the nearest square centimeter? (
-\dfrac{1}{6} \times \left(-\dfrac{9}{7}\right)− 6 1 ×(− 7 9 )minus, start fraction, 1, divided by, 6, end fraction, times, left parenthesis, minus, start fraction, 9, divided by, 7, end fraction, right parenthesis
What are the solutions of the equation x4 – 5x2 – 14 = 0? Use factoring to solve.
Which point is the image of Q ?ABCD

during unusual cold weather the temperature in Miami Beach was 10 this was 12 degrees more than in tallahassee what is the temperature in tallahassee

Answers

Miami Beach = 10°

This was 12° more than in Tallahassee.

Miami, 10° = 12° + Tallahassee

10° = 12° + T

10° - 12° = T

-2° = T

Temperature in Tallahassee is -2°

-2 degrees in Tallahassee

10-12=-2

85)A new car worth $20,000 loses 20% of its value every year. Is the value of the car represented by a linear or exponential
function?

Answers

You would represent this using a linear function. You would use a linear function because it deacreases at a steady rate

Based on the information marked in the diagram, ABCD and AEFG must becongruent.
С
17
E
A. True
B. False

Answers

The answer is A. True

The tuition costs, C, for a local community college are modeled by C(h) = 250 + 200h, where h represents the number of credit hours taken. The local state university has tuition costs, S, modeled by the function S(h) = 300 + 180h. How many credit hours will a student have to take for the two tuition costs to be equal? Round the answer to the nearest tenth of an hour. 250 + 200h = 300 + 180h 250 + 200h = 300 + 180h − 180h − 180h 250 + 20h = 300 h = credit hours

Answers

To solve how many credit hours will a student have to take for the two tuition costs to be equal, the two functions should be equated and solve for the number of hours
C (h) = S (h)
250 + 200h = 300 + 180h
200h – 180h = 300 – 250
20h = 50
H = 2.5 credit hours

The required equation is: $\mathbf{150 + 200h = 300 + 180h}$ and the number of credit hours is 7.5