MATHEMATICS HIGH SCHOOL

Janet measured a shopping center and made a scale drawing. The scale she used was 1 inch : 6 feet. A bakery in the shopping center is 13 inches in the drawing. How long is the actual bakery?

Answers

Answer 1

Answer:

The length of the actual bakery is 936 inches or 78 feet

Step-by-step explanation:

From the question we are told:

Janet measured a shopping center and made a scale drawing. The scale she used was 1 inch : 6 feet.

Let both the measurement of the shopping center and scale drawing be written in feet

1 foot = 12 inches

6 foot = x

Cross Multiply

x = 6 × 12 inches

x = 72 inches

Hence, the scale drawing =

Scale drawing : shopping center

1 inch = 72 inches

A bakery in the shopping center is 13 inches in the drawing. How long is the actual bakery?

This is calculated as:

1 inch = 72 inches

13 inches = x inches

Cross Multiply

x = 13 × 72 inches

x = 936 inches

The length of the shopping center = 936 inches

We convert back to feet

= 12 inches = 1foot

936 inches = x

Cross Multiply

12x = 936 × 1

x = 936/12

x = 78 feet

Therefore the length of the actual bakery is 936 inches or 78 feet

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Describe how to write 3x + 2y = 12

Answers

Subtract 3x from both sides of the equation and you should end up with 2y=-3x+12 After that divide 2y by everything which would give you y=-3x/2+6 I believe that's how to solve it

4x^2 + 8x - 11x + 6 - 5x^2 + 2A. -x^2 - 3x + 8
B. -x^2 + 3x + 8
C. x^2 - 3x + 8
D. x^2 + 3x + 8

Answers

I like to change all the subtraction to addition of the negative.
4x^2 + 8x + (-11x) + 6 + (-5x^2) + 2
Now combine the like terms.
-x^2 -3x + 8

Your answer is A: -x^2 - 3x + 8

4x^2 + 8x - 11x + 6 - 5x^2 + 2
(4x^2 - 5x^2) + (8x - 11x) + 6 + 2
-x^2 - 3x + 6 + 2
-x^2 - 3x + 8

The answer is: -x^2 - 3x + 8.

An alloy of tin is 15% tin and weighs 20 pounds. A second alloy is 10% tin. How many pounds of the second alloy must be added to the first to get a 12% mixture? 30 lb 40 lb 60 lb

Answers

so, they alloy is hmmm some piece of metal.

it has tin, among other metals, regardless of what other metals it may have, we know that for the first one, 15% is tin, the rest something else, and we also know that the alloy itself, weights 20 lbs.

now, how much is just the weight of the tin metal in it alone? well, is 15% of 20 lbs, or (15/100) * 20, or 3 lbs, so of all those 20 lbs, only 3 lbs or 15% is tin.

for the second alloy, let's say we'll add "x" lbs, we know the second alloy is 10% tin, how much of that weight is tin? well 10% of x, or (10/100) * x, or 0.10x lbs.

now, we're looking for a mixture, say the resulting lbs of mix will be "y" lbs, and we know the mixture will be 12% of tin, how much is 12% of y? (12/100) * y, or 0.12y.

now, regardless of what "x" and "y" is, we know that 20 + x = y, and that 3 + 0.10x = 0.12y, thus

$\bf \begin{array}{lccclll} &\stackrel{lbs}{amount}&\stackrel{tin~\%}{quantity}&\stackrel{tin~lbs}{quantity}\n &------&------&------\n \textit{15\% alloy}&20&0.15&3\n \textit{10\% alloy}&x&0.10&0.10x\n ------&------&------&------\n mixture&y&0.12&0.12y \end{array} \n\n\n \begin{cases} 20+x=\boxed{y}\n 3+0.10x=0.12y\n ----------\n 3+0.10x=0.12\left( \boxed{20+x} \right) \end{cases} \n\n\n 3+0.10x=2.4+0.12x\implies 3-2.4=0.12x-0.10x \n\n\n 0.6=0.02x\implies \cfrac{0.6}{0.02}=x\implies 30=x$

Answer:

30 lb

Step-by-step explanation:

Suppose JK bisects angle LJM. The measure of angle LJK = (-10x + 3) and the measure of KJM = (-x + 21)º. Find the measure of angle LJM.

Answers

LJK = KJM -10x +3 = -x + 21 -10x + x = 21 - 3 -9x = 18 x = -2 KJM = -x + 21 = 2 + 21 = 23 LJM = LJK + KJM LJM = 23 + 23 LJM = 46º..

i think thats how its done

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Answers

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